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Examples

$y = 5 x + 2$ , $2 y = 2 x + 15$ , $(1, 7)$

Step 1

Simplify $5 (1) + 2$ .

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Step 1.1

Multiply $5$ by $1$ .

$7 = 5 + 2$

$2 (7) = 2 (1) + 15$

Step 1.2

Add $5$ and $2$ .

$7 = 7$

$2 (7) = 2 (1) + 15$

$7 = 7$

$2 (7) = 2 (1) + 15$

Step 2

Since $7 = 7$ , the equation will always be true.

Always true

$2 (7) = 2 (1) + 15$

Step 3

Multiply $2$ by $7$ .

$14 = 2 (1) + 15$

Always true

Step 4

Simplify $2 (1) + 15$ .

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Step 4.1

Multiply $2$ by $1$ .

$14 = 2 + 15$

Always true

Step 4.2

Add $2$ and $15$ .

$14 = 17$

Always true

$14 = 17$

Always true

Step 5

Since $14 \neq 17$ , there are no solutions.

No solution

Step 6

The ordered pair is not a solution to the system of equations.

$(1, 7)$ is not a solution

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$