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Pre-Algebra Examples

(y^{2} + 6 y + 8) - (y^{2} + y - 12)

$(y^{2} + 6 y + 8) - (y^{2} + y - 12)$

Step 1

Simplify each term.

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Step 1.1

Apply the distributive property.

y^{2} + 6 y + 8 - y^{2} - y - - 12

$y^{2} + 6 y + 8 - y^{2} - y - - 12$

Step 1.2

Multiply

- 1

$- 1$ by

- 12

$- 12$ .

y^{2} + 6 y + 8 - y^{2} - y + 12

$y^{2} + 6 y + 8 - y^{2} - y + 12$

y^{2} + 6 y + 8 - y^{2} - y + 12

$y^{2} + 6 y + 8 - y^{2} - y + 12$

Step 2

Simplify by adding terms.

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Step 2.1

Combine the opposite terms in

y^{2} + 6 y + 8 - y^{2} - y + 12

$y^{2} + 6 y + 8 - y^{2} - y + 12$ .

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Step 2.1.1

Subtract

y^{2}

$y^{2}$ from

y^{2}

$y^{2}$ .

6 y + 8 + 0 - y + 12

$6 y + 8 + 0 - y + 12$

Step 2.1.2

Add

6 y + 8

$6 y + 8$ and

0

$0$ .

6 y + 8 - y + 12

$6 y + 8 - y + 12$

6 y + 8 - y + 12

$6 y + 8 - y + 12$

Step 2.2

Subtract

y

$y$ from

6 y

$6 y$ .

5 y + 8 + 12

$5 y + 8 + 12$

Step 2.3

Add

8

$8$ and

12

$12$ .

5 y + 20

$5 y + 20$

5 y + 20

$5 y + 20$

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⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$