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Pre-Algebra Examples

(x^{2} - 9) - (x^{2} - 5 x + 6)

$(x^{2} - 9) - (x^{2} - 5 x + 6)$

Step 1

Simplify each term.

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Step 1.1

Apply the distributive property.

x^{2} - 9 - x^{2} - (- 5 x) - 1 \cdot 6

$x^{2} - 9 - x^{2} - (- 5 x) - 1 \cdot 6$

Step 1.2

Simplify.

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Step 1.2.1

Multiply

- 5

$- 5$ by

- 1

$- 1$ .

x^{2} - 9 - x^{2} + 5 x - 1 \cdot 6

$x^{2} - 9 - x^{2} + 5 x - 1 \cdot 6$

Step 1.2.2

Multiply

- 1

$- 1$ by

6

$6$ .

x^{2} - 9 - x^{2} + 5 x - 6

$x^{2} - 9 - x^{2} + 5 x - 6$

x^{2} - 9 - x^{2} + 5 x - 6

$x^{2} - 9 - x^{2} + 5 x - 6$

x^{2} - 9 - x^{2} + 5 x - 6

$x^{2} - 9 - x^{2} + 5 x - 6$

Step 2

Simplify by adding terms.

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Step 2.1

Combine the opposite terms in

x^{2} - 9 - x^{2} + 5 x - 6

$x^{2} - 9 - x^{2} + 5 x - 6$ .

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Step 2.1.1

Subtract

x^{2}

$x^{2}$ from

x^{2}

$x^{2}$ .

0 - 9 + 5 x - 6

$0 - 9 + 5 x - 6$

Step 2.1.2

Subtract

9

$9$ from

0

$0$ .

- 9 + 5 x - 6

$- 9 + 5 x - 6$

- 9 + 5 x - 6

$- 9 + 5 x - 6$

Step 2.2

Subtract

6

$6$ from

- 9

$- 9$ .

5 x - 15

$5 x - 15$

5 x - 15

$5 x - 15$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$