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Pre-Algebra Examples

7 + y = - 2 y - 2

$7 + y = - 2 y - 2$

Step 1

Move all terms containing

y

$y$ to the left side of the equation.

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Step 1.1

Add

2 y

$2 y$ to both sides of the equation.

7 + y + 2 y = - 2

$7 + y + 2 y = - 2$

Step 1.2

Add

y

$y$ and

2 y

$2 y$ .

7 + 3 y = - 2

$7 + 3 y = - 2$

7 + 3 y = - 2

$7 + 3 y = - 2$

Step 2

Move all terms not containing

y

$y$ to the right side of the equation.

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Step 2.1

Subtract

7

$7$ from both sides of the equation.

3 y = - 2 - 7

$3 y = - 2 - 7$

Step 2.2

Subtract

7

$7$ from

- 2

$- 2$ .

3 y = - 9

$3 y = - 9$

3 y = - 9

$3 y = - 9$

Step 3

Divide each term in

3 y = - 9

$3 y = - 9$ by

3

$3$ and simplify.

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Step 3.1

Divide each term in

3 y = - 9

$3 y = - 9$ by

3

$3$ .

\frac{3 y}{3} = \frac{- 9}{3}

$\frac{3 y}{3} = \frac{- 9}{3}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of

3

$3$ .

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Step 3.2.1.1

Cancel the common factor.

\frac{3 y}{3} = \frac{- 9}{3}

$\frac{3 y}{3} = \frac{- 9}{3}$

Step 3.2.1.2

Divide

y

$y$ by

1

$1$ .

y = \frac{- 9}{3}

$y = \frac{- 9}{3}$

y = \frac{- 9}{3}

$y = \frac{- 9}{3}$

y = \frac{- 9}{3}

$y = \frac{- 9}{3}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Divide

- 9

$- 9$ by

3

$3$ .

y = - 3

$y = - 3$

y = - 3

$y = - 3$

y = - 3

$y = - 3$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$