Pre-Algebra Examples

 $\begin{array}{r} h = & 5 \\ r = & 1 \end{array}$

Step 1

The surface area of a cone is equal to the area of the base plus the area of the cone.

$(π \cdot (r a d i u s)) \cdot ((r a d i u s) + \sqrt{{(r a d i u s)}^{2} + {(h e i g h t)}^{2}})$

Step 2

Substitute the values of the length $r = 1$ and height $h = 5$ into the formula. Pi $π$ is approximately equal to $3.14$ .

$(π \cdot 1) (1 + \sqrt{{(1)}^{2} + {(5)}^{2}})$

Step 3

Multiply $π$ by $1$ .

$π (1 + \sqrt{{(1)}^{2} + {(5)}^{2}})$

Step 4

Simplify each term.

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Step 4.1

One to any power is one.

$π (1 + \sqrt{1 + {(5)}^{2}})$

Step 4.2

Raise $5$ to the power of $2$ .

$π (1 + \sqrt{1 + 25})$

Step 4.3

Add $1$ and $25$ .

$π (1 + \sqrt{26})$

Step 5

Simplify by multiplying through.

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Step 5.1

Apply the distributive property.

$π \cdot 1 + π \sqrt{26}$

Step 5.2

Multiply $π$ by $1$ .

$π + π \sqrt{26}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$π + π \sqrt{26}$

Decimal Form:

$19.16063489 \dots$

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