Pre-Algebra Examples

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$\begin{array}{r} h = & 9 \\ l = & 5 \\ w = & 4 \end{array}$

Step 1

The surface area of a box is equal to the sum of the areas of each side of the box.

$2 \cdot (l e n g t h) \cdot (w i d t h) + 2 \cdot (l e n g t h) \cdot (h e i g h t) + 2 \cdot (w i d t h) \cdot (h e i g h t)$

Step 2

Substitute the values of the length

$l = 5$ , the width

$w = 4$ , and the height

$h = 9$ into the formula.

$2 \cdot 5 \cdot 4 + 2 \cdot 5 \cdot 9 + 2 \cdot 4 \cdot 9$

Step 3

Simplify each term.

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Step 3.1

Multiply

$2 \cdot 5 \cdot 4$ .

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Step 3.1.1

Multiply

$2$ by

$5$ .

$10 \cdot 4 + 2 \cdot 5 \cdot 9 + 2 \cdot 4 \cdot 9$

Step 3.1.2

Multiply

$10$ by

$4$ .

$40 + 2 \cdot 5 \cdot 9 + 2 \cdot 4 \cdot 9$

Step 3.2

Multiply

$2 \cdot 5 \cdot 9$ .

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Step 3.2.1

Multiply

$2$ by

$5$ .

$40 + 10 \cdot 9 + 2 \cdot 4 \cdot 9$

Step 3.2.2

Multiply

$10$ by

$9$ .

$40 + 90 + 2 \cdot 4 \cdot 9$

Step 3.3

Multiply

$2 \cdot 4 \cdot 9$ .

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Step 3.3.1

Multiply

$2$ by

$4$ .

$40 + 90 + 8 \cdot 9$

Step 3.3.2

Multiply

$8$ by

$9$ .

$40 + 90 + 72$

Step 4

Simplify by adding numbers.

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Step 4.1

Add

$40$ and

$90$ .

$130 + 72$

Step 4.2

Add

$130$ and

$72$ .

$202$

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