Pre-Algebra Examples

 $\begin{array}{r} b_{1} = & 6 \\ b_{2} = & 9 \\ h = & 2 \end{array}$

Step 1

The area of a trapezoid is equal to $\frac{1}{2}$ times the height times the sum of the bases $b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height $h = 2$ and bases ( $b_{1} = 6$ and $b_{2} = 9$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 2 \cdot (6 + 9)$

Step 3

Cancel the common factor of $2$ .

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Step 3.1

Cancel the common factor.

$\frac{1}{2} \cdot 2 \cdot (6 + 9)$

Step 3.2

Rewrite the expression.

$1 \cdot (6 + 9)$

Step 4

Simplify the expression.

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Step 4.1

Multiply $6 + 9$ by $1$ .

$6 + 9$

Step 4.2

Add $6$ and $9$ .

$15$

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