Pre-Algebra Examples

y = 3 x + 1

$y = 3 x + 1$

Step 1

Substitute

- 2

$- 2$ for

x

$x$ and find the result for

y

$y$ .

y = 3 (- 2) + 1

$y = 3 (- 2) + 1$

Step 2

Simplify

3 (- 2) + 1

$3 (- 2) + 1$ .

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Step 2.1

Multiply

3

$3$ by

- 2

$- 2$ .

y = - 6 + 1

$y = - 6 + 1$

Step 2.2

Add

- 6

$- 6$ and

1

$1$ .

y = - 5

$y = - 5$

y = - 5

$y = - 5$

Step 3

Substitute

- 1

$- 1$ for

x

$x$ and find the result for

y

$y$ .

y = 3 (- 1) + 1

$y = 3 (- 1) + 1$

Step 4

Simplify

3 (- 1) + 1

$3 (- 1) + 1$ .

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Step 4.1

Multiply

3

$3$ by

- 1

$- 1$ .

y = - 3 + 1

$y = - 3 + 1$

Step 4.2

Add

- 3

$- 3$ and

1

$1$ .

y = - 2

$y = - 2$

y = - 2

$y = - 2$

Step 5

Substitute

0

$0$ for

x

$x$ and find the result for

y

$y$ .

y = 3 (0) + 1

$y = 3 (0) + 1$

Step 6

Solve the equation for

y

$y$ .

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Step 6.1

Remove parentheses.

y = 3 (0) + 1

$y = 3 (0) + 1$

Step 6.2

Simplify

3 (0) + 1

$3 (0) + 1$ .

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Step 6.2.1

Multiply

3

$3$ by

0

$0$ .

y = 0 + 1

$y = 0 + 1$

Step 6.2.2

Add

0

$0$ and

1

$1$ .

y = 1

$y = 1$

y = 1

$y = 1$

y = 1

$y = 1$

Step 7

Substitute

1

$1$ for

x

$x$ and find the result for

y

$y$ .

y = 3 (1) + 1

$y = 3 (1) + 1$

Step 8

Solve the equation for

y

$y$ .

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Step 8.1

Remove parentheses.

y = 3 (1) + 1

$y = 3 (1) + 1$

Step 8.2

Simplify

3 (1) + 1

$3 (1) + 1$ .

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Step 8.2.1

Multiply

3

$3$ by

1

$1$ .

y = 3 + 1

$y = 3 + 1$

Step 8.2.2

Add

3

$3$ and

1

$1$ .

y = 4

$y = 4$

y = 4

$y = 4$

y = 4

$y = 4$

Step 9

Substitute

2

$2$ for

x

$x$ and find the result for

y

$y$ .

y = 3 (2) + 1

$y = 3 (2) + 1$

Step 10

Solve the equation for

y

$y$ .

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Step 10.1

Remove parentheses.

y = 3 (2) + 1

$y = 3 (2) + 1$

Step 10.2

Simplify

3 (2) + 1

$3 (2) + 1$ .

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Step 10.2.1

Multiply

3

$3$ by

2

$2$ .

y = 6 + 1

$y = 6 + 1$

Step 10.2.2

Add

6

$6$ and

1

$1$ .

y = 7

$y = 7$

y = 7

$y = 7$

y = 7

$y = 7$

Step 11

This is a table of possible values to use when graphing the equation.

\begin{matrix} x & y - 2 & - 5 - 1 & - 2 0 & 1 1 & 4 2 & 7 \end{matrix}

$\begin{array}{c} x & y \\ - 2 & - 5 \\ - 1 & - 2 \\ 0 & 1 \\ 1 & 4 \\ 2 & 7 \end{array}$

Step 12

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