Pre-Algebra Examples

x - y + 4 = 8

$x - y + 4 = 8$

Step 1

The slope-intercept form is

y = m x + b

$y = m x + b$ , where

m

$m$ is the slope and

b

$b$ is the y-intercept.

y = m x + b

$y = m x + b$

Step 2

Rewrite in slope-intercept form.

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Step 2.1

Move all terms not containing

y

$y$ to the right side of the equation.

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Step 2.1.1

Subtract

x

$x$ from both sides of the equation.

- y + 4 = 8 - x

$- y + 4 = 8 - x$

Step 2.1.2

Subtract

4

$4$ from both sides of the equation.

- y = 8 - x - 4

$- y = 8 - x - 4$

Step 2.1.3

Subtract

4

$4$ from

8

$8$ .

- y = - x + 4

$- y = - x + 4$

- y = - x + 4

$- y = - x + 4$

Step 2.2

Divide each term in

- y = - x + 4

$- y = - x + 4$ by

- 1

$- 1$ and simplify.

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Step 2.2.1

Divide each term in

- y = - x + 4

$- y = - x + 4$ by

- 1

$- 1$ .

\frac{- y}{- 1} = \frac{- x}{- 1} + \frac{4}{- 1}

$\frac{- y}{- 1} = \frac{- x}{- 1} + \frac{4}{- 1}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Dividing two negative values results in a positive value.

\frac{y}{1} = \frac{- x}{- 1} + \frac{4}{- 1}

$\frac{y}{1} = \frac{- x}{- 1} + \frac{4}{- 1}$

Step 2.2.2.2

Divide

y

$y$ by

1

$1$ .

y = \frac{- x}{- 1} + \frac{4}{- 1}

$y = \frac{- x}{- 1} + \frac{4}{- 1}$

y = \frac{- x}{- 1} + \frac{4}{- 1}

$y = \frac{- x}{- 1} + \frac{4}{- 1}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Simplify each term.

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Step 2.2.3.1.1

Dividing two negative values results in a positive value.

y = \frac{x}{1} + \frac{4}{- 1}

$y = \frac{x}{1} + \frac{4}{- 1}$

Step 2.2.3.1.2

Divide

x

$x$ by

1

$1$ .

y = x + \frac{4}{- 1}

$y = x + \frac{4}{- 1}$

Step 2.2.3.1.3

Divide

4

$4$ by

- 1

$- 1$ .

y = x - 4

$y = x - 4$

y = x - 4

$y = x - 4$

y = x - 4

$y = x - 4$

y = x - 4

$y = x - 4$

y = x - 4

$y = x - 4$

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