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Pre-Algebra Examples

m = \frac{1}{2}

$m = \frac{1}{2}$ ,

(0, 9)

$(0, 9)$

Step 1

Find the value of

b

$b$ using the formula for the equation of a line.

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Step 1.1

Use the formula for the equation of a line to find

b

$b$ .

y = m x + b

$y = m x + b$

Step 1.2

Substitute the value of

m

$m$ into the equation.

y = (\frac{1}{2}) x + b

$y = (\frac{1}{2}) x + b$

Step 1.3

Substitute the value of

x

$x$ into the equation.

y = (\frac{1}{2}) \cdot (0) + b

$y = (\frac{1}{2}) \cdot (0) + b$

Step 1.4

Substitute the value of

y

$y$ into the equation.

9 = (\frac{1}{2}) \cdot (0) + b

$9 = (\frac{1}{2}) \cdot (0) + b$

Step 1.5

Find the value of

b

$b$ .

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Step 1.5.1

Rewrite the equation as

\frac{1}{2} \cdot 0 + b = 9

$\frac{1}{2} \cdot 0 + b = 9$ .

\frac{1}{2} \cdot 0 + b = 9

$\frac{1}{2} \cdot 0 + b = 9$

Step 1.5.2

Simplify

\frac{1}{2} \cdot 0 + b

$\frac{1}{2} \cdot 0 + b$ .

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Step 1.5.2.1

Multiply

\frac{1}{2}

$\frac{1}{2}$ by

0

$0$ .

0 + b = 9

$0 + b = 9$

Step 1.5.2.2

Add

0

$0$ and

b

$b$ .

b = 9

$b = 9$

b = 9

$b = 9$

b = 9

$b = 9$

b = 9

$b = 9$

Step 2

Now that the values of

m

$m$ (slope) and

b

$b$ (y-intercept) are known, substitute them into

y = m x + b

$y = m x + b$ to find the equation of the line.

y = \frac{1}{2} x + 9

$y = \frac{1}{2} x + 9$

Step 3

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$