Physics Examples

Find the Final Displacement
x=x0+v0t+12at2x=x0+v0t+12at2
xx==??
x0x0==0m0m
v0v0==1ms1ms
tt==3s3s
aa==-9.8ms29.8ms2
Step 1
Substitute the given values into x=x0+v0t+12at2x=x0+v0t+12at2.
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Step 1.1
Substitute 0m0m for x0x0.
x=0m+v0t+12at2x=0m+v0t+12at2
Step 1.2
Substitute 1ms1ms for v0v0.
x=0m+1mst+12at2x=0m+1mst+12at2
Step 1.3
Substitute 3s3s for tt.
x=0m+1ms3.0s+12a(3.0s)2x=0m+1ms3.0s+12a(3.0s)2
Step 1.4
Substitute -9.8ms29.8ms2 for aa.
x=0m+1ms3.0s+12(-9.8ms2)(3.0s)2x=0m+1ms3.0s+12(9.8ms2)(3.0s)2
x=0m+1.0ms3.0s+12(-9.8ms2)(3.0s)2x=0m+1.0ms3.0s+12(9.8ms2)(3.0s)2
Step 2
Simplify the right side.
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Step 2.1
Simplify each term.
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Step 2.1.1
Cross cancel units.
x=0m+1.0ms3.0s1+12(-9.8ms2)(3.0s)2
Step 2.1.2
Simplify the expression.
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Step 2.1.2.1
Remove the canceled units.
x=0m+1.0m13.01+12(-9.8ms2)(3.0s)2
Step 2.1.2.2
Combine fractions.
x=0m+3.0m+12(-9.8ms2)(3.0s)2
x=0m+3.0m+12(-9.8ms2)(3.0s)2
Step 2.1.3
Combine fractions.
x=0m+3.0m+(3.0s)2-9.82ms2
Step 2.1.4
Simplify the numerator.
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Step 2.1.4.1
Apply the product rule to 3.0s.
x=0m+3.0m+3.02s2-9.82ms2
Step 2.1.4.2
Multiply -9.8 by 3.02.
x=0m+3.0m+-88.2s22ms2
x=0m+3.0m+-88.2s22ms2
Step 2.1.5
Cross cancel units.
x=0m+3.0m+-88.2s22ms2
Step 2.1.6
Remove the canceled units.
x=0m+3.0m+-88.22m1
Step 2.1.7
Combine fractions.
x=0m+3.0m+-88.22m
Step 2.1.8
Divide -88.2 by 2.
x=0m+3.0m-44.1m
x=0m+3.0m-44.1m
Step 2.2
Add 0m and 3.0m.
x=3.0m-44.1m
Step 2.3
Subtract 44.1m from 3.0m.
x=-41.1m
x=-41.1m
Step 3
Round to 2 significant figures.
x=-41m
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 [x2  12  π  xdx ] 
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