Physics Examples
V=IR
V | = | ? |
I | = | 0.55A |
R | = | 4⋅102Ω |
Step 1
Step 1.1
Substitute 0.55A for I.
V=0.55AR
Step 1.2
Substitute 4⋅102Ω for R.
V=0.55A(4⋅102Ω)
V=0.550A(4.0⋅102Ω)
Step 2
Step 2.1
Multiply 4.0 by 0.550.
V=2.2000A(102Ω)
Step 2.2
Raise 10 to the power of 2.
V=2.2000A(100Ω)
Step 2.3
Multiply 100 by 2.2000.
V=220.0000(AΩ)
Step 2.4
Rewrite AΩ as V.
V=220.0000V
V=220.0000V
Step 3
Round to 2 significant figures.
V=2.2⋅102V