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Examples

y = 5 x + 2

$y = 5 x + 2$ ,

2 y = 2 x + 12

$2 y = 2 x + 12$ ,

(1, 7)

$(1, 7)$

Step 1

Simplify

5 (1) + 2

$5 (1) + 2$ .

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Step 1.1

Multiply

5

$5$ by

1

$1$ .

7 = 5 + 2

$7 = 5 + 2$

2 (7) = 2 (1) + 12

$2 (7) = 2 (1) + 12$

Step 1.2

Add

5

$5$ and

2

$2$ .

7 = 7

$7 = 7$

2 (7) = 2 (1) + 12

$2 (7) = 2 (1) + 12$

7 = 7

$7 = 7$

2 (7) = 2 (1) + 12

$2 (7) = 2 (1) + 12$

Step 2

Since

7 = 7

$7 = 7$ , the equation will always be true.

Always true

2 (7) = 2 (1) + 12

$2 (7) = 2 (1) + 12$

Step 3

Multiply

2

$2$ by

7

$7$ .

14 = 2 (1) + 12

$14 = 2 (1) + 12$

Always true

Step 4

Simplify

2 (1) + 12

$2 (1) + 12$ .

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Step 4.1

Multiply

2

$2$ by

1

$1$ .

14 = 2 + 12

$14 = 2 + 12$

Always true

Step 4.2

Add

2

$2$ and

12

$12$ .

14 = 14

$14 = 14$

Always true

14 = 14

$14 = 14$

Always true

Step 5

Since

14 = 14

$14 = 14$ , the equation will always be true.

Always true

Always true

Step 6

The ordered pair is a solution to the system of equations.

(1, 7)

$(1, 7)$ is a solution

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$