Examples
y=3x-21 , (-7,0)
Step 1
Step 1.1
The slope-intercept form is y=mx+b, where m is the slope and b is the y-intercept.
y=mx+b
Step 1.2
Using the slope-intercept form, the slope is 3.
m=3
m=3
Step 2
The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.
mperpendicular=-13
Step 3
Step 3.1
Use the slope -13 and a given point (-7,0) to substitute for x1 and y1 in the point-slope form y-y1=m(x-x1), which is derived from the slope equation m=y2-y1x2-x1.
y-(0)=-13⋅(x-(-7))
Step 3.2
Simplify the equation and keep it in point-slope form.
y+0=-13⋅(x+7)
y+0=-13⋅(x+7)
Step 4
Step 4.1
Solve for y.
Step 4.1.1
Add y and 0.
y=-13⋅(x+7)
Step 4.1.2
Simplify -13⋅(x+7).
Step 4.1.2.1
Apply the distributive property.
y=-13x-13⋅7
Step 4.1.2.2
Combine x and 13.
y=-x3-13⋅7
Step 4.1.2.3
Multiply -13⋅7.
Step 4.1.2.3.1
Multiply 7 by -1.
y=-x3-7(13)
Step 4.1.2.3.2
Combine -7 and 13.
y=-x3+-73
y=-x3+-73
Step 4.1.2.4
Move the negative in front of the fraction.
y=-x3-73
y=-x3-73
y=-x3-73
Step 4.2
Reorder terms.
y=-(13x)-73
Step 4.3
Remove parentheses.
y=-13x-73
y=-13x-73
Step 5