Examples

Find the Factors Using the Factor Theorem
x3-3x2-2x+6 , x-3
Step 1
Divide x3-3x2-2x+6x-3 using synthetic division and check if the remainder is equal to 0. If the remainder is equal to 0, it means that x-3 is a factor for x3-3x2-2x+6. If the remainder is not equal to 0, it means that x-3 is not a factor for x3-3x2-2x+6.
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Step 1.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
31-3-26
  
Step 1.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
31-3-26
  
1
Step 1.3
Multiply the newest entry in the result (1) by the divisor (3) and place the result of (3) under the next term in the dividend (-3).
31-3-26
 3 
1
Step 1.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
31-3-26
 3 
10
Step 1.5
Multiply the newest entry in the result (0) by the divisor (3) and place the result of (0) under the next term in the dividend (-2).
31-3-26
 30 
10
Step 1.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
31-3-26
 30 
10-2
Step 1.7
Multiply the newest entry in the result (-2) by the divisor (3) and place the result of (-6) under the next term in the dividend (6).
31-3-26
 30-6
10-2
Step 1.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
31-3-26
 30-6
10-20
Step 1.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x2+0x-2
Step 1.10
Simplify the quotient polynomial.
x2-2
x2-2
Step 2
The remainder from dividing x3-3x2-2x+6x-3 is 0, which means that x-3 is a factor for x3-3x2-2x+6.
x-3 is a factor for x3-3x2-2x+6
Step 3
Find all the possible roots for x2-2.
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Step 3.1
If a polynomial function has integer coefficients, then every rational zero will have the form pq where p is a factor of the constant and q is a factor of the leading coefficient.
p=±1,±2
q=±1
Step 3.2
Find every combination of ±pq. These are the possible roots of the polynomial function.
±1,±2
±1,±2
Step 4
The final factor is the only factor left over from the synthetic division.
x2-2
Step 5
The factored polynomial is (x-3)(x2-2).
(x-3)(x2-2)
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 [x2  12  π  xdx ] 
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