Finite Math Examples
(-4,8)(−4,8) , (-2,5)(−2,5)
Step 1
To find the position vector, subtract the initial point vector PP from the terminal point vector QQ.
Q-P=(-2i+5j)-(-4i+8j)Q−P=(−2i+5j)−(−4i+8j)
Step 2
Step 2.1
Apply the distributive property.
-2i+5j-(-4i)-(8j)−2i+5j−(−4i)−(8j)
Step 2.2
Multiply -4−4 by -1−1.
-2i+5j+4i-(8j)−2i+5j+4i−(8j)
Step 2.3
Multiply 88 by -1−1.
-2i+5j+4i-8j−2i+5j+4i−8j
-2i+5j+4i-8j−2i+5j+4i−8j
Step 3
Step 3.1
Add -2i−2i and 4i4i.
5j+2i-8j5j+2i−8j
Step 3.2
Subtract 8j8j from 5j5j.
-3j+2i−3j+2i
-3j+2i−3j+2i
Step 4