Finite Math Examples

(1, 4)

$(1, 4)$ ,

(13, 6)

$(13, 6)$

Step 1

To find the position vector, subtract the initial point vector

P

$P$ from the terminal point vector

Q

$Q$ .

Q - P = (13 i + 6 j) - (1 i + 4 j)

$Q - P = (13 i + 6 j) - (1 i + 4 j)$

Step 2

Simplify each term.

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Step 2.1

Multiply

i

$i$ by

1

$1$ .

13 i + 6 j - (i + 4 j)

$13 i + 6 j - (i + 4 j)$

Step 2.2

Apply the distributive property.

13 i + 6 j - i - (4 j)

$13 i + 6 j - i - (4 j)$

Step 2.3

Multiply

4

$4$ by

- 1

$- 1$ .

13 i + 6 j - i - 4 j

$13 i + 6 j - i - 4 j$

13 i + 6 j - i - 4 j

$13 i + 6 j - i - 4 j$

Step 3

Simplify by adding terms.

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Step 3.1

Subtract

i

$i$ from

13 i

$13 i$ .

6 j + 12 i - 4 j

$6 j + 12 i - 4 j$

Step 3.2

Subtract

4 j

$4 j$ from

6 j

$6 j$ .

2 j + 12 i

$2 j + 12 i$

2 j + 12 i

$2 j + 12 i$

Step 4

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