Finite Math Examples

[\begin{matrix} 2 & 0 3 & 1 \end{matrix}]

$[\begin{array}{c} 2 & 0 \\ 3 & 1 \end{array}]$

Step 1

The inverse of a

2 \times 2

$2 \times 2$ matrix can be found using the formula

\frac{1}{a d - b c} [\begin{matrix} d & - b - c & a \end{matrix}]

$\frac{1}{a d - b c} [\begin{array}{c} d & - b \\ - c & a \end{array}]$ where

a d - b c

$a d - b c$ is the determinant.

Step 2

Find the determinant.

Tap for more steps...

Step 2.1

The determinant of a

2 \times 2

$2 \times 2$ matrix can be found using the formula

∣ ∣ ∣ \begin{matrix} a & b c & d \end{matrix} ∣ ∣ ∣ = a d - c b

$| \begin{array}{c} a & b \\ c & d \end{array} | = a d - c b$ .

2 \cdot 1 - 3 \cdot 0

$2 \cdot 1 - 3 \cdot 0$

Step 2.2

Simplify the determinant.

Tap for more steps...

Step 2.2.1

Simplify each term.

Tap for more steps...

Step 2.2.1.1

Multiply

2

$2$ by

1

$1$ .

2 - 3 \cdot 0

$2 - 3 \cdot 0$

Step 2.2.1.2

Multiply

- 3

$- 3$ by

0

$0$ .

2 + 0

$2 + 0$

2 + 0

$2 + 0$

Step 2.2.2

Add

2

$2$ and

0

$0$ .

2

$2$

2

$2$

2

$2$

Step 3

Since the determinant is non-zero, the inverse exists.

Step 4

Substitute the known values into the formula for the inverse.

\frac{1}{2} [\begin{matrix} 1 & 0 - 3 & 2 \end{matrix}]

$\frac{1}{2} [\begin{array}{c} 1 & 0 \\ - 3 & 2 \end{array}]$

Step 5

Multiply

\frac{1}{2}

$\frac{1}{2}$ by each element of the matrix.

[\begin{matrix} \frac{1}{2} \cdot 1 & \frac{1}{2} \cdot 0 \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{matrix}]

$[\begin{array}{c} \frac{1}{2} \cdot 1 & \frac{1}{2} \cdot 0 \\ \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{array}]$

Step 6

Simplify each element in the matrix.

Tap for more steps...

Step 6.1

Multiply

\frac{1}{2}

$\frac{1}{2}$ by

1

$1$ .

[\begin{matrix} \frac{1}{2} & \frac{1}{2} \cdot 0 \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{matrix}]

$[\begin{array}{c} \frac{1}{2} & \frac{1}{2} \cdot 0 \\ \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{array}]$

Step 6.2

Multiply

\frac{1}{2}

$\frac{1}{2}$ by

0

$0$ .

[\begin{matrix} \frac{1}{2} & 0 \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{matrix}]

$[\begin{array}{c} \frac{1}{2} & 0 \\ \frac{1}{2} \cdot - 3 & \frac{1}{2} \cdot 2 \end{array}]$

Step 6.3

Combine

\frac{1}{2}

$\frac{1}{2}$ and

- 3

$- 3$ .

[\begin{matrix} \frac{1}{2} & 0 \frac{- 3}{2} & \frac{1}{2} \cdot 2 \end{matrix}]

$[\begin{array}{c} \frac{1}{2} & 0 \\ \frac{- 3}{2} & \frac{1}{2} \cdot 2 \end{array}]$

Step 6.4

Move the negative in front of the fraction.

[\begin{matrix} \frac{1}{2} & 0 - \frac{3}{2} & \frac{1}{2} \cdot 2 \end{matrix}]

$[\begin{array}{c} \frac{1}{2} & 0 \\ - \frac{3}{2} & \frac{1}{2} \cdot 2 \end{array}]$

Step 6.5

Cancel the common factor of

2

$2$ .

Tap for more steps...

Step 6.5.1

Cancel the common factor.

$[\begin{array}{c} \frac{1}{2} & 0 \\ - \frac{3}{2} & \frac{1}{2} \cdot 2 \end{array}]$

Step 6.5.2

Rewrite the expression.

$[\begin{array}{c} \frac{1}{2} & 0 \\ - \frac{3}{2} & 1 \end{array}]$

Enter YOUR Problem