Finite Math Examples

(1, - 7)

$(1, - 7)$ ,

m = 12

$m = 12$

Step 1

Use the slope

12

$12$ and a given point

(1, - 7)

$(1, - 7)$ to substitute for

x_{1}

$x_{1}$ and

y_{1}

$y_{1}$ in the point-slope form

y - y_{1} = m (x - x_{1})

$y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

y - (- 7) = 12 \cdot (x - (1))

$y - (- 7) = 12 \cdot (x - (1))$

Step 2

Simplify the equation and keep it in point-slope form.

y + 7 = 12 \cdot (x - 1)

$y + 7 = 12 \cdot (x - 1)$

Step 3

Solve for

y

$y$ .

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Step 3.1

Simplify

12 \cdot (x - 1)

$12 \cdot (x - 1)$ .

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Step 3.1.1

Rewrite.

y + 7 = 0 + 0 + 12 \cdot (x - 1)

$y + 7 = 0 + 0 + 12 \cdot (x - 1)$

Step 3.1.2

Simplify by adding zeros.

y + 7 = 12 \cdot (x - 1)

$y + 7 = 12 \cdot (x - 1)$

Step 3.1.3

Apply the distributive property.

y + 7 = 12 x + 12 \cdot - 1

$y + 7 = 12 x + 12 \cdot - 1$

Step 3.1.4

Multiply

12

$12$ by

- 1

$- 1$ .

y + 7 = 12 x - 12

$y + 7 = 12 x - 12$

y + 7 = 12 x - 12

$y + 7 = 12 x - 12$

Step 3.2

Move all terms not containing

y

$y$ to the right side of the equation.

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Step 3.2.1

Subtract

7

$7$ from both sides of the equation.

y = 12 x - 12 - 7

$y = 12 x - 12 - 7$

Step 3.2.2

Subtract

7

$7$ from

- 12

$- 12$ .

y = 12 x - 19

$y = 12 x - 19$

y = 12 x - 19

$y = 12 x - 19$

y = 12 x - 19

$y = 12 x - 19$

Step 4

List the equation in different forms.

Slope-intercept form:

y = 12 x - 19

$y = 12 x - 19$

Point-slope form:

y + 7 = 12 \cdot (x - 1)

$y + 7 = 12 \cdot (x - 1)$

Step 5

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