Finite Math Examples
3232 , 1515 , 2727 , 1818 , 1616 , 2424 , 3636 , 2121 , 4242 , 3232 , 4646 , 1515 , 1717 , 3838 , 4242 , 1515 , 2424 , 3737 , 2323 , 5656 , 1717 , 3636 , n=8n=8
Step 1
Find the data range by subtracting the minimum data value from the maximum data value. In this case, the data range is 56-15=4156−15=41.
4141
Step 2
Find the class width by dividing the data range by the desired number of groups. In this case, 418=5.125418=5.125.
5.1255.125
Step 3
Round 5.1255.125 up to the nearest whole number. This will be the size of each group.
66
Step 4
Start with 1515 and create 88 groups of size 66.
ClassClassBoundariesFrequency15-2021-2627-3233-3839-4445-5051-5657-62ClassClassBoundariesFrequency15−2021−2627−3233−3839−4445−5051−5657−62
Step 5
Determine the class boundaries by subtracting 0.50.5 from the lower class limit and by adding 0.50.5 to the upper class limit.
ClassClassBoundariesFrequency15-2014.5-20.521-2620.5-26.527-3226.5-32.533-3832.5-38.539-4438.5-44.545-5044.5-50.551-5650.5-56.557-6256.5-62.5ClassClassBoundariesFrequency15−2014.5−20.521−2620.5−26.527−3226.5−32.533−3832.5−38.539−4438.5−44.545−5044.5−50.551−5650.5−56.557−6256.5−62.5
Step 6
Draw a tally mark next to each class for each value that is contained within that class.
ClassClassBoundariesFrequency15-2014.5-20.5|||||||21-2620.5-26.5||||27-3226.5-32.5|||33-3832.5-38.5||||39-4438.5-44.5||45-5044.5-50.5|51-5650.5-56.5|57-6256.5-62.5ClassClassBoundariesFrequency15−2014.5−20.5|||||||21−2620.5−26.5||||27−3226.5−32.5|||33−3832.5−38.5||||39−4438.5−44.5||45−5044.5−50.5|51−5650.5−56.5|57−6256.5−62.5
Step 7
Count the tally marks to determine the frequency of each class.
ClassClassBoundariesFrequency15-2014.5-20.5721-2620.5-26.5427-3226.5-32.5333-3832.5-38.5439-4438.5-44.5245-5044.5-50.5151-5650.5-56.5157-6256.5-62.50ClassClassBoundariesFrequency15−2014.5−20.5721−2620.5−26.5427−3226.5−32.5333−3832.5−38.5439−4438.5−44.5245−5044.5−50.5151−5650.5−56.5157−6256.5−62.50
