Finite Math Examples

7

$7$ ,

4

$4$ ,

1

$1$ ,

8

$8$ ,

n = 3

$n = 3$

Step 1

Find the data range by subtracting the minimum data value from the maximum data value. In this case, the data range is

8 - 1 = 7

$8 - 1 = 7$ .

7

$7$

Step 2

Find the class width by dividing the data range by the desired number of groups. In this case,

\frac{7}{3} = 2.\overline{3}

$\frac{7}{3} = 2.\overline{3}$ .

2.\overline{3}

$2.\overline{3}$

Step 3

Round

2.\overline{3}

$2.\overline{3}$ up to the nearest whole number. This will be the size of each group.

3

$3$

Step 4

Start with

1

$1$ and create

3

$3$ groups of size

3

$3$ .

\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 \\ 4 - 6 \\ 7 - 9 \end{array}

$\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 \\ 4 - 6 \\ 7 - 9 \end{array}$

Step 5

Determine the class boundaries by subtracting

0.5

$0.5$ from the lower class limit and by adding

0.5

$0.5$ to the upper class limit.

\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 \\ 4 - 6 & 3.5 - 6.5 \\ 7 - 9 & 6.5 - 9.5 \end{array}

$\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 \\ 4 - 6 & 3.5 - 6.5 \\ 7 - 9 & 6.5 - 9.5 \end{array}$

Step 6

Draw a tally mark next to each class for each value that is contained within that class.

\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 & | \\ 4 - 6 & 3.5 - 6.5 & | \\ 7 - 9 & 6.5 - 9.5 & | | \end{array}

$\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 & | \\ 4 - 6 & 3.5 - 6.5 & | \\ 7 - 9 & 6.5 - 9.5 & | | \end{array}$

Step 7

Count the tally marks to determine the frequency of each class.

\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 & 1 \\ 4 - 6 & 3.5 - 6.5 & 1 \\ 7 - 9 & 6.5 - 9.5 & 2 \end{array}

$\begin{array}{c} Class & Class Boundaries & Frequency \\ 1 - 3 & 0.5 - 3.5 & 1 \\ 4 - 6 & 3.5 - 6.5 & 1 \\ 7 - 9 & 6.5 - 9.5 & 2 \end{array}$

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