Finite Math Examples

2

$2$ ,

4

$4$ ,

6

$6$ ,

8

$8$ ,

10

$10$ ,

12

$12$ ,

14

$14$

Step 1

The mid-range or mid-extreme of a set of statistical data values is the average of the maximum and minimum values.

Mid-Range = \frac{Maximum + Minimum}{2}

$Mid-Range = \frac{Maximum + Minimum}{2}$

Step 2

Substitute the values of maximum

14

$14$ and minimum

2

$2$ into the equation.

Mid-Range = \frac{14 + 2}{2}

$Mid-Range = \frac{14 + 2}{2}$

Step 3

Cancel the common factor of

14 + 2

$14 + 2$ and

2

$2$ .

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Step 3.1

Factor

2

$2$ out of

14

$14$ .

Mid-Range = \frac{2 \cdot 7 + 2}{2}

$Mid-Range = \frac{2 \cdot 7 + 2}{2}$

Step 3.2

Factor

2

$2$ out of

2

$2$ .

Mid-Range = \frac{2 \cdot 7 + 2 \cdot 1}{2}

$Mid-Range = \frac{2 \cdot 7 + 2 \cdot 1}{2}$

Step 3.3

Factor

2

$2$ out of

2 \cdot 7 + 2 \cdot 1

$2 \cdot 7 + 2 \cdot 1$ .

Mid-Range = \frac{2 \cdot (7 + 1)}{2}

$Mid-Range = \frac{2 \cdot (7 + 1)}{2}$

Step 3.4

Cancel the common factors.

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Step 3.4.1

Factor

2

$2$ out of

2

$2$ .

Mid-Range = \frac{2 \cdot (7 + 1)}{2 (1)}

$Mid-Range = \frac{2 \cdot (7 + 1)}{2 (1)}$

Step 3.4.2

Cancel the common factor.

Mid-Range = \frac{2 \cdot (7 + 1)}{2 \cdot 1}

$Mid-Range = \frac{2 \cdot (7 + 1)}{2 \cdot 1}$

Step 3.4.3

Rewrite the expression.

Mid-Range = \frac{7 + 1}{1}

$Mid-Range = \frac{7 + 1}{1}$

Step 3.4.4

Divide

7 + 1

$7 + 1$ by

1

$1$ .

Mid-Range = 7 + 1

$Mid-Range = 7 + 1$

Mid-Range = 7 + 1

$Mid-Range = 7 + 1$

Mid-Range = 7 + 1

$Mid-Range = 7 + 1$

Step 4

Add

7

$7$ and

1

$1$ .

Mid-Range = 8

$Mid-Range = 8$

Step 5

Convert

8

$8$ to decimal.

Mid-Range = 8

$Mid-Range = 8$

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