Chemistry Examples

$C a O$

Step 1

To find the mass of $1$ mole of $C a O$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $C a O$ $=$ $(mass of Ca)$ + $(mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $C a O$ $=$ $(40.08000183)$ + $(16)$

Step 3

Simplify the result.

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Step 3.1

Remove parentheses.

mass of $1$ mole of $C a O = 40.08000183 + 16 g$

Step 3.2

Add $40.08000183$ and $16$ .

mass of $1$ mole of $C a O = 56.08000183 g$

Step 4

Find the mass percentage of $C a$ .

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Step 4.1

The mass composition percentage is the mass of $C a$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C a = \frac{40.08}{56.08000183} \cdot 100$

Step 4.2

Divide $40.08$ by $56.08000183$ .

$0.71469327 \cdot 100$

Step 4.3

Multiply $0.71469327$ by $100$ .

$71.46932719$

Step 4.4

Set the number as a percent.

Mass percentage of $C a = 71.46932719 %$

Step 5

Find the mass percentage of $O$ .

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Step 5.1

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{16}{56.08000183} \cdot 100$

Step 5.2

Divide $16$ by $56.08000183$ .

$0.28530669 \cdot 100$

Step 5.3

Multiply $0.28530669$ by $100$ .

$28.53066953$

Step 5.4

Set the number as a percent.

Mass percentage of $O = 28.53066953 %$

Step 6

Find the mass percentage of each element in the molecule.

Mass percentage of $C a = 71.46932719 %$

Mass percentage of $O = 28.53066953 %$

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