Examples

x^{2} + 3 y = 0

$x^{2} + 3 y = 0$ ,

y = 5

$y = 5$ ,

(3, 4)

$(3, 4)$

Step 1

Simplify

3^{2} + 3 (4)

$3^{2} + 3 (4)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Raise

3

$3$ to the power of

2

$2$ .

9 + 3 (4) = 0

$9 + 3 (4) = 0$

4 = 5

$4 = 5$

Step 1.1.2

Multiply

3

$3$ by

4

$4$ .

9 + 12 = 0

$9 + 12 = 0$

4 = 5

$4 = 5$

9 + 12 = 0

$9 + 12 = 0$

4 = 5

$4 = 5$

Step 1.2

Add

9

$9$ and

12

$12$ .

21 = 0

$21 = 0$

4 = 5

$4 = 5$

21 = 0

$21 = 0$

4 = 5

$4 = 5$

Step 2

Since

21 \neq 0

$21 \neq 0$ , there are no solutions.

No solution

Step 3

Since

4 \neq 5

$4 \neq 5$ , there are no solutions.

No solution

Step 4

The ordered pair is not a solution to the system of equations.

(3, 4)

$(3, 4)$ is not a solution

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