Examples

Solve by Addition/Elimination
x+y=4 , x-y=2
Step 1
Multiply each equation by the value that makes the coefficients of x opposite.
x+y=4
(-1)(x-y)=(-1)(2)
Step 2
Simplify.
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Step 2.1
Simplify the left side.
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Step 2.1.1
Simplify (-1)(x-y).
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Step 2.1.1.1
Apply the distributive property.
x+y=4
-1x-1(-y)=(-1)(2)
Step 2.1.1.2
Rewrite -1x as -x.
x+y=4
-x-1(-y)=(-1)(2)
Step 2.1.1.3
Multiply -1(-y).
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Step 2.1.1.3.1
Multiply -1 by -1.
x+y=4
-x+1y=(-1)(2)
Step 2.1.1.3.2
Multiply y by 1.
x+y=4
-x+y=(-1)(2)
x+y=4
-x+y=(-1)(2)
x+y=4
-x+y=(-1)(2)
x+y=4
-x+y=(-1)(2)
Step 2.2
Simplify the right side.
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Step 2.2.1
Multiply -1 by 2.
x+y=4
-x+y=-2
x+y=4
-x+y=-2
x+y=4
-x+y=-2
Step 3
Add the two equations together to eliminate x from the system.
x+y=4
+-x+y=-2
2y=2
Step 4
Divide each term in 2y=2 by 2 and simplify.
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Step 4.1
Divide each term in 2y=2 by 2.
2y2=22
Step 4.2
Simplify the left side.
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Step 4.2.1
Cancel the common factor of 2.
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Step 4.2.1.1
Cancel the common factor.
2y2=22
Step 4.2.1.2
Divide y by 1.
y=22
y=22
y=22
Step 4.3
Simplify the right side.
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Step 4.3.1
Divide 2 by 2.
y=1
y=1
y=1
Step 5
Substitute the value found for y into one of the original equations, then solve for x.
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Step 5.1
Substitute the value found for y into one of the original equations to solve for x.
x+1=4
Step 5.2
Move all terms not containing x to the right side of the equation.
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Step 5.2.1
Subtract 1 from both sides of the equation.
x=4-1
Step 5.2.2
Subtract 1 from 4.
x=3
x=3
x=3
Step 6
The solution to the independent system of equations can be represented as a point.
(3,1)
Step 7
The result can be shown in multiple forms.
Point Form:
(3,1)
Equation Form:
x=3,y=1
Step 8
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 [x2  12  π  xdx ]