Examples
x3−3x2−2x+6 , x−4
Step 1
Step 1.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
4 | 1 | −3 | −2 | 6 |
Step 1.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
4 | 1 | −3 | −2 | 6 |
1 |
Step 1.3
Multiply the newest entry in the result (1) by the divisor (4) and place the result of (4) under the next term in the dividend (−3).
4 | 1 | −3 | −2 | 6 |
4 | ||||
1 |
Step 1.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | −3 | −2 | 6 |
4 | ||||
1 | 1 |
Step 1.5
Multiply the newest entry in the result (1) by the divisor (4) and place the result of (4) under the next term in the dividend (−2).
4 | 1 | −3 | −2 | 6 |
4 | 4 | |||
1 | 1 |
Step 1.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | −3 | −2 | 6 |
4 | 4 | |||
1 | 1 | 2 |
Step 1.7
Multiply the newest entry in the result (2) by the divisor (4) and place the result of (8) under the next term in the dividend (6).
4 | 1 | −3 | −2 | 6 |
4 | 4 | 8 | ||
1 | 1 | 2 |
Step 1.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | −3 | −2 | 6 |
4 | 4 | 8 | ||
1 | 1 | 2 | 14 |
Step 1.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x2+1x+2+14x−4
Step 1.10
Simplify the quotient polynomial.
x2+x+2+14x−4
x2+x+2+14x−4
Step 2
The remainder from dividing x3−3x2−2x+6x−4 is 14, which is not equal to 0. The remainder is not equal to 0 means that x−4 is not a factor for x3−3x2−2x+6.
x−4 is not a factor for x3−3x2−2x+6