Calculus Examples

Find the Sum of the First 6 Terms
2 , 5 , 8 , 11 , 14
Step 1
This is the formula to find the sum of the first n terms of the sequence. To evaluate it, the values of the first and nth terms must be found.
Sn=n2(a1+an)
Step 2
This is an arithmetic sequence since there is a common difference between each term. In this case, adding 3 to the previous term in the sequence gives the next term. In other words, an=a1+d(n-1).
Arithmetic Sequence: d=3
Step 3
This is the formula of an arithmetic sequence.
an=a1+d(n-1)
Step 4
Substitute in the values of a1=2 and d=3.
an=2+3(n-1)
Step 5
Simplify each term.
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Step 5.1
Apply the distributive property.
an=2+3n+3-1
Step 5.2
Multiply 3 by -1.
an=2+3n-3
an=2+3n-3
Step 6
Subtract 3 from 2.
an=3n-1
Step 7
Substitute in the value of n to find the nth term.
a7=3(7)-1
Step 8
Multiply 3 by 7.
a7=21-1
Step 9
Subtract 1 from 21.
a7=20
Step 10
Replace the variables with the known values to find S7.
S7=72(2+20)
Step 11
Add 2 and 20.
S7=7222
Step 12
Cancel the common factor of 2.
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Step 12.1
Factor 2 out of 22.
S7=72(2(11))
Step 12.2
Cancel the common factor.
S7=72(211)
Step 12.3
Rewrite the expression.
S7=711
S7=711
Step 13
Multiply 7 by 11.
S7=77
Step 14
Convert the fraction to a decimal.
S7=77
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 [x2  12  π  xdx ] 
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