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Calculus Examples

f (x) = x + 4

$f (x) = x + 4$ ,

f (x) = 3 x

$f (x) = 3 x$

Step 1

Substitute

3 x

$3 x$ for

f (x)

$f (x)$ .

3 x = x + 4

$3 x = x + 4$

Step 2

Solve for

x

$x$ .

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Step 2.1

Move all terms containing

x

$x$ to the left side of the equation.

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Step 2.1.1

Subtract

x

$x$ from both sides of the equation.

3 x - x = 4

$3 x - x = 4$

Step 2.1.2

Subtract

x

$x$ from

3 x

$3 x$ .

2 x = 4

$2 x = 4$

2 x = 4

$2 x = 4$

Step 2.2

Divide each term in

2 x = 4

$2 x = 4$ by

2

$2$ and simplify.

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Step 2.2.1

Divide each term in

2 x = 4

$2 x = 4$ by

2

$2$ .

\frac{2 x}{2} = \frac{4}{2}

$\frac{2 x}{2} = \frac{4}{2}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of

2

$2$ .

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Step 2.2.2.1.1

Cancel the common factor.

\frac{2 x}{2} = \frac{4}{2}

$\frac{2 x}{2} = \frac{4}{2}$

Step 2.2.2.1.2

Divide

x

$x$ by

1

$1$ .

x = \frac{4}{2}

$x = \frac{4}{2}$

x = \frac{4}{2}

$x = \frac{4}{2}$

x = \frac{4}{2}

$x = \frac{4}{2}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Divide

4

$4$ by

2

$2$ .

x = 2

$x = 2$

x = 2

$x = 2$

x = 2

$x = 2$

x = 2

$x = 2$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$