Calculus Examples

$f (x) = 5 x^{2} + 6$

Step 1

Find

$f (- x)$ .

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Step 1.1

Find

$f (- x)$ by substituting

$- x$ for all occurrence of

$x$ in

$f (x)$ .

$f (- x) = 5 {(- x)}^{2} + 6$

Step 1.2

Simplify each term.

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Step 1.2.1

Apply the product rule to

$- x$ .

$f (- x) = 5 ({(- 1)}^{2} x^{2}) + 6$

Step 1.2.2

Raise

$- 1$ to the power of

$2$ .

$f (- x) = 5 (1 x^{2}) + 6$

Step 1.2.3

Multiply

$x^{2}$ by

$1$ .

$f (- x) = 5 x^{2} + 6$

Step 2

A function is even if

$f (- x) = f (x)$ .

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Step 2.1

Check if

$f (- x) = f (x)$ .

Step 2.2

Since

$5 x^{2} + 6 = 5 x^{2} + 6$ , the function is even.

The function is even

Step 3

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