Calculus Examples
y=7x(3-x) , x=3
Step 1
Since 7 is constant with respect to x, the derivative of 7x(3-x) with respect to x is 7ddx[x(3-x)].
7ddx[x(3-x)]
Step 2
Differentiate using the Product Rule which states that ddx[f(x)g(x)] is f(x)ddx[g(x)]+g(x)ddx[f(x)] where f(x)=x and g(x)=3-x.
7(xddx[3-x]+(3-x)ddx[x])
Step 3
Step 3.1
By the Sum Rule, the derivative of 3-x with respect to x is ddx[3]+ddx[-x].
7(x(ddx[3]+ddx[-x])+(3-x)ddx[x])
Step 3.2
Since 3 is constant with respect to x, the derivative of 3 with respect to x is 0.
7(x(0+ddx[-x])+(3-x)ddx[x])
Step 3.3
Add 0 and ddx[-x].
7(xddx[-x]+(3-x)ddx[x])
Step 3.4
Since -1 is constant with respect to x, the derivative of -x with respect to x is -ddx[x].
7(x(-ddx[x])+(3-x)ddx[x])
Step 3.5
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
7(x(-1⋅1)+(3-x)ddx[x])
Step 3.6
Simplify the expression.
Step 3.6.1
Multiply -1 by 1.
7(x⋅-1+(3-x)ddx[x])
Step 3.6.2
Move -1 to the left of x.
7(-1⋅x+(3-x)ddx[x])
Step 3.6.3
Rewrite -1x as -x.
7(-x+(3-x)ddx[x])
7(-x+(3-x)ddx[x])
Step 3.7
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
7(-x+(3-x)⋅1)
Step 3.8
Simplify by adding terms.
Step 3.8.1
Multiply 3-x by 1.
7(-x+3-x)
Step 3.8.2
Subtract x from -x.
7(-2x+3)
7(-2x+3)
7(-2x+3)
Step 4
Step 4.1
Apply the distributive property.
7(-2x)+7⋅3
Step 4.2
Combine terms.
Step 4.2.1
Multiply -2 by 7.
-14x+7⋅3
Step 4.2.2
Multiply 7 by 3.
-14x+21
-14x+21
-14x+21
Step 5
Evaluate the derivative at x=3.
-14⋅3+21
Step 6
Step 6.1
Multiply -14 by 3.
-42+21
Step 6.2
Add -42 and 21.
-21
-21