Calculus Examples

$f (x) = 5 x^{4} - 10 x^{2}$

Step 1

Find the second derivative.

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Step 1.1

Find the first derivative.

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Step 1.1.1

By the Sum Rule, the derivative of

$5 x^{4} - 10 x^{2}$ with respect to

$x$ is

$\frac{d}{d x} [5 x^{4}] + \frac{d}{d x} [- 10 x^{2}]$ .

$f' (x) = \frac{d}{d x} (5 x^{4}) + \frac{d}{d x} (- 10 x^{2})$

Step 1.1.2

Evaluate

$\frac{d}{d x} [5 x^{4}]$ .

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Step 1.1.2.1

Since

$5$ is constant with respect to

$x$ , the derivative of

$5 x^{4}$ with respect to

$x$ is

$5 \frac{d}{d x} [x^{4}]$ .

$f' (x) = 5 \frac{d}{d x} (x^{4}) + \frac{d}{d x} (- 10 x^{2})$

Step 1.1.2.2

Differentiate using the Power Rule which states that

$\frac{d}{d x} [x^{n}]$ is

$n x^{n - 1}$ where

$n = 4$ .

$f' (x) = 5 (4 x^{3}) + \frac{d}{d x} (- 10 x^{2})$

Step 1.1.2.3

Multiply

$4$ by

$5$ .

$f' (x) = 20 x^{3} + \frac{d}{d x} (- 10 x^{2})$

Step 1.1.3

Evaluate

$\frac{d}{d x} [- 10 x^{2}]$ .

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Step 1.1.3.1

Since

$- 10$ is constant with respect to

$x$ , the derivative of

$- 10 x^{2}$ with respect to

$x$ is

$- 10 \frac{d}{d x} [x^{2}]$ .

$f' (x) = 20 x^{3} - 10 \frac{d}{d x} x^{2}$

Step 1.1.3.2

Differentiate using the Power Rule which states that

$\frac{d}{d x} [x^{n}]$ is

$n x^{n - 1}$ where

$n = 2$ .

$f' (x) = 20 x^{3} - 10 (2 x)$

Step 1.1.3.3

Multiply

$2$ by

$- 10$ .

$f' (x) = 20 x^{3} - 20 x$

Step 1.2

Find the second derivative.

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Step 1.2.1

By the Sum Rule, the derivative of

$20 x^{3} - 20 x$ with respect to

$x$ is

$\frac{d}{d x} [20 x^{3}] + \frac{d}{d x} [- 20 x]$ .

$f'' (x) = \frac{d}{d x} (20 x^{3}) + \frac{d}{d x} (- 20 x)$

Step 1.2.2

Evaluate

$\frac{d}{d x} [20 x^{3}]$ .

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Step 1.2.2.1

Since

$20$ is constant with respect to

$x$ , the derivative of

$20 x^{3}$ with respect to

$x$ is

$20 \frac{d}{d x} [x^{3}]$ .

$f'' (x) = 20 \frac{d}{d x} (x^{3}) + \frac{d}{d x} (- 20 x)$

Step 1.2.2.2

Differentiate using the Power Rule which states that

$\frac{d}{d x} [x^{n}]$ is

$n x^{n - 1}$ where

$n = 3$ .

$f'' (x) = 20 (3 x^{2}) + \frac{d}{d x} (- 20 x)$

Step 1.2.2.3

Multiply

$3$ by

$20$ .

$f'' (x) = 60 x^{2} + \frac{d}{d x} (- 20 x)$

Step 1.2.3

Evaluate

$\frac{d}{d x} [- 20 x]$ .

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Step 1.2.3.1

Since

$- 20$ is constant with respect to

$x$ , the derivative of

$- 20 x$ with respect to

$x$ is

$- 20 \frac{d}{d x} [x]$ .

$f'' (x) = 60 x^{2} - 20 \frac{d}{d x} x$

Step 1.2.3.2

Differentiate using the Power Rule which states that

$\frac{d}{d x} [x^{n}]$ is

$n x^{n - 1}$ where

$n = 1$ .

$f'' (x) = 60 x^{2} - 20 \cdot 1$

Step 1.2.3.3

Multiply

$- 20$ by

$1$ .

$f'' (x) = 60 x^{2} - 20$

Step 1.3

The second derivative of

$f (x)$ with respect to

$x$ is

$60 x^{2} - 20$ .

$60 x^{2} - 20$

Step 2

Set the second derivative equal to

$0$ then solve the equation

$60 x^{2} - 20 = 0$ .

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Step 2.1

Set the second derivative equal to

$0$ .

$60 x^{2} - 20 = 0$

Step 2.2

Add

$20$ to both sides of the equation.

$60 x^{2} = 20$

Step 2.3

Divide each term in

$60 x^{2} = 20$ by

$60$ and simplify.

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Step 2.3.1

Divide each term in

$60 x^{2} = 20$ by

$60$ .

$\frac{60 x^{2}}{60} = \frac{20}{60}$

Step 2.3.2

Simplify the left side.

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Step 2.3.2.1

Cancel the common factor of

$60$ .

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Step 2.3.2.1.1

Cancel the common factor.

$\frac{60 x^{2}}{60} = \frac{20}{60}$

Step 2.3.2.1.2

Divide

$x^{2}$ by

$1$ .

$x^{2} = \frac{20}{60}$

Step 2.3.3

Simplify the right side.

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Step 2.3.3.1

Cancel the common factor of

$20$ and

$60$ .

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Step 2.3.3.1.1

Factor

$20$ out of

$20$ .

$x^{2} = \frac{20 (1)}{60}$

Step 2.3.3.1.2

Cancel the common factors.

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Step 2.3.3.1.2.1

Factor

$20$ out of

$60$ .

$x^{2} = \frac{20 \cdot 1}{20 \cdot 3}$

Step 2.3.3.1.2.2

Cancel the common factor.

$x^{2} = \frac{20 \cdot 1}{20 \cdot 3}$

Step 2.3.3.1.2.3

Rewrite the expression.

$x^{2} = \frac{1}{3}$

Step 2.4

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{\frac{1}{3}}$

Step 2.5

Simplify

$\pm \sqrt{\frac{1}{3}}$ .

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Step 2.5.1

Rewrite

$\sqrt{\frac{1}{3}}$ as

$\frac{\sqrt{1}}{\sqrt{3}}$ .

$x = \pm \frac{\sqrt{1}}{\sqrt{3}}$

Step 2.5.2

Any root of

$1$ is

$1$ .

$x = \pm \frac{1}{\sqrt{3}}$

Step 2.5.3

Multiply

$\frac{1}{\sqrt{3}}$ by

$\frac{\sqrt{3}}{\sqrt{3}}$ .

$x = \pm \frac{1}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}}$

Step 2.5.4

Combine and simplify the denominator.

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Step 2.5.4.1

Multiply

$\frac{1}{\sqrt{3}}$ by

$\frac{\sqrt{3}}{\sqrt{3}}$ .

$x = \pm \frac{\sqrt{3}}{\sqrt{3} \sqrt{3}}$

Step 2.5.4.2

Raise

$\sqrt{3}$ to the power of

$1$ .

$x = \pm \frac{\sqrt{3}}{{\sqrt{3}}^{1} \sqrt{3}}$

Step 2.5.4.3

Raise

$\sqrt{3}$ to the power of

$1$ .

$x = \pm \frac{\sqrt{3}}{{\sqrt{3}}^{1} {\sqrt{3}}^{1}}$

Step 2.5.4.4

Use the power rule

$a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x = \pm \frac{\sqrt{3}}{{\sqrt{3}}^{1 + 1}}$

Step 2.5.4.5

Add

$1$ and

$1$ .

$x = \pm \frac{\sqrt{3}}{{\sqrt{3}}^{2}}$

Step 2.5.4.6

Rewrite

${\sqrt{3}}^{2}$ as

$3$ .

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Step 2.5.4.6.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{3}$ as

$3^{\frac{1}{2}}$ .

$x = \pm \frac{\sqrt{3}}{{(3^{\frac{1}{2}})}^{2}}$

Step 2.5.4.6.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$x = \pm \frac{\sqrt{3}}{3^{\frac{1}{2} \cdot 2}}$

Step 2.5.4.6.3

Combine

$\frac{1}{2}$ and

$2$ .

$x = \pm \frac{\sqrt{3}}{3^{\frac{2}{2}}}$

Step 2.5.4.6.4

Cancel the common factor of

$2$ .

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Step 2.5.4.6.4.1

Cancel the common factor.

$x = \pm \frac{\sqrt{3}}{3^{\frac{2}{2}}}$

Step 2.5.4.6.4.2

Rewrite the expression.

$x = \pm \frac{\sqrt{3}}{3^{1}}$

Step 2.5.4.6.5

Evaluate the exponent.

$x = \pm \frac{\sqrt{3}}{3}$

Step 2.6

The complete solution is the result of both the positive and negative portions of the solution.

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Step 2.6.1

First, use the positive value of the

$\pm$ to find the first solution.

$x = \frac{\sqrt{3}}{3}$

Step 2.6.2

Next, use the negative value of the

$\pm$ to find the second solution.

$x = - \frac{\sqrt{3}}{3}$

Step 2.6.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = \frac{\sqrt{3}}{3}, - \frac{\sqrt{3}}{3}$

Step 3

Find the points where the second derivative is

$0$ .

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Step 3.1

Substitute

$\frac{\sqrt{3}}{3}$ in

$f (x) = 5 x^{4} - 10 x^{2}$ to find the value of

$y$ .

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Step 3.1.1

Replace the variable

$x$ with

$\frac{\sqrt{3}}{3}$ in the expression.

$f (\frac{\sqrt{3}}{3}) = 5 {(\frac{\sqrt{3}}{3})}^{4} - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2

Simplify the result.

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Step 3.1.2.1

Simplify each term.

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Step 3.1.2.1.1

Apply the product rule to

$\frac{\sqrt{3}}{3}$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{{\sqrt{3}}^{4}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2

Simplify the numerator.

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Step 3.1.2.1.2.1

Rewrite

${\sqrt{3}}^{4}$ as

$3^{2}$ .

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Step 3.1.2.1.2.1.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{3}$ as

$3^{\frac{1}{2}}$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{{(3^{\frac{1}{2}})}^{4}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{1}{2} \cdot 4}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.3

Combine

$\frac{1}{2}$ and

$4$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{4}{2}}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.4

Cancel the common factor of

$4$ and

$2$ .

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Step 3.1.2.1.2.1.4.1

Factor

$2$ out of

$4$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2}}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.4.2

Cancel the common factors.

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Step 3.1.2.1.2.1.4.2.1

Factor

$2$ out of

$2$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2 (1)}}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.4.2.2

Cancel the common factor.

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2 \cdot 1}}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.4.2.3

Rewrite the expression.

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2}{1}}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.1.4.2.4

Divide

$2$ by

$1$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{3^{2}}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.2.2

Raise

$3$ to the power of

$2$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{9}{3^{4}}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.3

Raise

$3$ to the power of

$4$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{9}{81}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.4

Cancel the common factor of

$9$ and

$81$ .

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Step 3.1.2.1.4.1

Factor

$9$ out of

$9$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{9 (1)}{81}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.4.2

Cancel the common factors.

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Step 3.1.2.1.4.2.1

Factor

$9$ out of

$81$ .

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{9 \cdot 1}{9 \cdot 9}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.4.2.2

Cancel the common factor.

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{9 \cdot 1}{9 \cdot 9}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.4.2.3

Rewrite the expression.

$f (\frac{\sqrt{3}}{3}) = 5 (\frac{1}{9}) - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.5

Combine

$5$ and

$\frac{1}{9}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 {(\frac{\sqrt{3}}{3})}^{2}$

Step 3.1.2.1.6

Apply the product rule to

$\frac{\sqrt{3}}{3}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{{\sqrt{3}}^{2}}{3^{2}}$

Step 3.1.2.1.7

Rewrite

${\sqrt{3}}^{2}$ as

$3$ .

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Step 3.1.2.1.7.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{3}$ as

$3^{\frac{1}{2}}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{{(3^{\frac{1}{2}})}^{2}}{3^{2}}$

Step 3.1.2.1.7.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{1}{2} \cdot 2}}{3^{2}}$

Step 3.1.2.1.7.3

Combine

$\frac{1}{2}$ and

$2$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{2}{2}}}{3^{2}}$

Step 3.1.2.1.7.4

Cancel the common factor of

$2$ .

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Step 3.1.2.1.7.4.1

Cancel the common factor.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{2}{2}}}{3^{2}}$

Step 3.1.2.1.7.4.2

Rewrite the expression.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3}{3^{2}}$

Step 3.1.2.1.7.5

Evaluate the exponent.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3}{3^{2}}$

Step 3.1.2.1.8

Raise

$3$ to the power of

$2$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 (\frac{3}{9})$

Step 3.1.2.1.9

Cancel the common factor of

$3$ and

$9$ .

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Step 3.1.2.1.9.1

Factor

$3$ out of

$3$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 (1)}{9}$

Step 3.1.2.1.9.2

Cancel the common factors.

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Step 3.1.2.1.9.2.1

Factor

$3$ out of

$9$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 \cdot 1}{3 \cdot 3}$

Step 3.1.2.1.9.2.2

Cancel the common factor.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 \cdot 1}{3 \cdot 3}$

Step 3.1.2.1.9.2.3

Rewrite the expression.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 (\frac{1}{3})$

Step 3.1.2.1.10

Combine

$- 10$ and

$\frac{1}{3}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} + \frac{- 10}{3}$

Step 3.1.2.1.11

Move the negative in front of the fraction.

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10}{3}$

Step 3.1.2.2

To write

$- \frac{10}{3}$ as a fraction with a common denominator, multiply by

$\frac{3}{3}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10}{3} \cdot \frac{3}{3}$

Step 3.1.2.3

Write each expression with a common denominator of

$9$ , by multiplying each by an appropriate factor of

$1$ .

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Step 3.1.2.3.1

Multiply

$\frac{10}{3}$ by

$\frac{3}{3}$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10 \cdot 3}{3 \cdot 3}$

Step 3.1.2.3.2

Multiply

$3$ by

$3$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10 \cdot 3}{9}$

Step 3.1.2.4

Combine the numerators over the common denominator.

$f (\frac{\sqrt{3}}{3}) = \frac{5 - 10 \cdot 3}{9}$

Step 3.1.2.5

Simplify the numerator.

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Step 3.1.2.5.1

Multiply

$- 10$ by

$3$ .

$f (\frac{\sqrt{3}}{3}) = \frac{5 - 30}{9}$

Step 3.1.2.5.2

Subtract

$30$ from

$5$ .

$f (\frac{\sqrt{3}}{3}) = \frac{- 25}{9}$

Step 3.1.2.6

Move the negative in front of the fraction.

$f (\frac{\sqrt{3}}{3}) = - \frac{25}{9}$

Step 3.1.2.7

The final answer is

$- \frac{25}{9}$ .

$- \frac{25}{9}$

Step 3.2

The point found by substituting

$\frac{\sqrt{3}}{3}$ in

$f (x) = 5 x^{4} - 10 x^{2}$ is

$(\frac{\sqrt{3}}{3}, - \frac{25}{9})$ . This point can be an inflection point.

$(\frac{\sqrt{3}}{3}, - \frac{25}{9})$

Step 3.3

Substitute

$- \frac{\sqrt{3}}{3}$ in

$f (x) = 5 x^{4} - 10 x^{2}$ to find the value of

$y$ .

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Step 3.3.1

Replace the variable

$x$ with

$- \frac{\sqrt{3}}{3}$ in the expression.

$f (- \frac{\sqrt{3}}{3}) = 5 {(- \frac{\sqrt{3}}{3})}^{4} - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2

Simplify the result.

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Step 3.3.2.1

Simplify each term.

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Step 3.3.2.1.1

Use the power rule

${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 3.3.2.1.1.1

Apply the product rule to

$- \frac{\sqrt{3}}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = 5 ({(- 1)}^{4} {(\frac{\sqrt{3}}{3})}^{4}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.1.2

Apply the product rule to

$\frac{\sqrt{3}}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = 5 ({(- 1)}^{4} (\frac{{\sqrt{3}}^{4}}{3^{4}})) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.2

Raise

$- 1$ to the power of

$4$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (1 (\frac{{\sqrt{3}}^{4}}{3^{4}})) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.3

Multiply

$\frac{{\sqrt{3}}^{4}}{3^{4}}$ by

$1$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{{\sqrt{3}}^{4}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4

Simplify the numerator.

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Step 3.3.2.1.4.1

Rewrite

${\sqrt{3}}^{4}$ as

$3^{2}$ .

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Step 3.3.2.1.4.1.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{3}$ as

$3^{\frac{1}{2}}$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{{(3^{\frac{1}{2}})}^{4}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{1}{2} \cdot 4}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.3

Combine

$\frac{1}{2}$ and

$4$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{4}{2}}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.4

Cancel the common factor of

$4$ and

$2$ .

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Step 3.3.2.1.4.1.4.1

Factor

$2$ out of

$4$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2}}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.4.2

Cancel the common factors.

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Step 3.3.2.1.4.1.4.2.1

Factor

$2$ out of

$2$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2 (1)}}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.4.2.2

Cancel the common factor.

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2 \cdot 2}{2 \cdot 1}}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.4.2.3

Rewrite the expression.

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{\frac{2}{1}}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.1.4.2.4

Divide

$2$ by

$1$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{3^{2}}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.4.2

Raise

$3$ to the power of

$2$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{9}{3^{4}}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.5

Raise

$3$ to the power of

$4$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{9}{81}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.6

Cancel the common factor of

$9$ and

$81$ .

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Step 3.3.2.1.6.1

Factor

$9$ out of

$9$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{9 (1)}{81}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.6.2

Cancel the common factors.

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Step 3.3.2.1.6.2.1

Factor

$9$ out of

$81$ .

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{9 \cdot 1}{9 \cdot 9}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.6.2.2

Cancel the common factor.

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{9 \cdot 1}{9 \cdot 9}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.6.2.3

Rewrite the expression.

$f (- \frac{\sqrt{3}}{3}) = 5 (\frac{1}{9}) - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.7

Combine

$5$ and

$\frac{1}{9}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 {(- \frac{\sqrt{3}}{3})}^{2}$

Step 3.3.2.1.8

Use the power rule

${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 3.3.2.1.8.1

Apply the product rule to

$- \frac{\sqrt{3}}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 ({(- 1)}^{2} {(\frac{\sqrt{3}}{3})}^{2})$

Step 3.3.2.1.8.2

Apply the product rule to

$\frac{\sqrt{3}}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 ({(- 1)}^{2} (\frac{{\sqrt{3}}^{2}}{3^{2}}))$

Step 3.3.2.1.9

Raise

$- 1$ to the power of

$2$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 (1 (\frac{{\sqrt{3}}^{2}}{3^{2}}))$

Step 3.3.2.1.10

Multiply

$\frac{{\sqrt{3}}^{2}}{3^{2}}$ by

$1$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{{\sqrt{3}}^{2}}{3^{2}}$

Step 3.3.2.1.11

Rewrite

${\sqrt{3}}^{2}$ as

$3$ .

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Step 3.3.2.1.11.1

Use

$\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite

$\sqrt{3}$ as

$3^{\frac{1}{2}}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{{(3^{\frac{1}{2}})}^{2}}{3^{2}}$

Step 3.3.2.1.11.2

Apply the power rule and multiply exponents,

${(a^{m})}^{n} = a^{m n}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{1}{2} \cdot 2}}{3^{2}}$

Step 3.3.2.1.11.3

Combine

$\frac{1}{2}$ and

$2$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{2}{2}}}{3^{2}}$

Step 3.3.2.1.11.4

Cancel the common factor of

$2$ .

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Step 3.3.2.1.11.4.1

Cancel the common factor.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3^{\frac{2}{2}}}{3^{2}}$

Step 3.3.2.1.11.4.2

Rewrite the expression.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3}{3^{2}}$

Step 3.3.2.1.11.5

Evaluate the exponent.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3}{3^{2}}$

Step 3.3.2.1.12

Raise

$3$ to the power of

$2$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 (\frac{3}{9})$

Step 3.3.2.1.13

Cancel the common factor of

$3$ and

$9$ .

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Step 3.3.2.1.13.1

Factor

$3$ out of

$3$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 (1)}{9}$

Step 3.3.2.1.13.2

Cancel the common factors.

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Step 3.3.2.1.13.2.1

Factor

$3$ out of

$9$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 \cdot 1}{3 \cdot 3}$

Step 3.3.2.1.13.2.2

Cancel the common factor.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 \frac{3 \cdot 1}{3 \cdot 3}$

Step 3.3.2.1.13.2.3

Rewrite the expression.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - 10 (\frac{1}{3})$

Step 3.3.2.1.14

Combine

$- 10$ and

$\frac{1}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} + \frac{- 10}{3}$

Step 3.3.2.1.15

Move the negative in front of the fraction.

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10}{3}$

Step 3.3.2.2

To write

$- \frac{10}{3}$ as a fraction with a common denominator, multiply by

$\frac{3}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10}{3} \cdot \frac{3}{3}$

Step 3.3.2.3

Write each expression with a common denominator of

$9$ , by multiplying each by an appropriate factor of

$1$ .

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Step 3.3.2.3.1

Multiply

$\frac{10}{3}$ by

$\frac{3}{3}$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10 \cdot 3}{3 \cdot 3}$

Step 3.3.2.3.2

Multiply

$3$ by

$3$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5}{9} - \frac{10 \cdot 3}{9}$

Step 3.3.2.4

Combine the numerators over the common denominator.

$f (- \frac{\sqrt{3}}{3}) = \frac{5 - 10 \cdot 3}{9}$

Step 3.3.2.5

Simplify the numerator.

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Step 3.3.2.5.1

Multiply

$- 10$ by

$3$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{5 - 30}{9}$

Step 3.3.2.5.2

Subtract

$30$ from

$5$ .

$f (- \frac{\sqrt{3}}{3}) = \frac{- 25}{9}$

Step 3.3.2.6

Move the negative in front of the fraction.

$f (- \frac{\sqrt{3}}{3}) = - \frac{25}{9}$

Step 3.3.2.7

The final answer is

$- \frac{25}{9}$ .

$- \frac{25}{9}$

Step 3.4

The point found by substituting

$- \frac{\sqrt{3}}{3}$ in

$f (x) = 5 x^{4} - 10 x^{2}$ is

$(- \frac{\sqrt{3}}{3}, - \frac{25}{9})$ . This point can be an inflection point.

$(- \frac{\sqrt{3}}{3}, - \frac{25}{9})$

Step 3.5

Determine the points that could be inflection points.

$(\frac{\sqrt{3}}{3}, - \frac{25}{9}), (- \frac{\sqrt{3}}{3}, - \frac{25}{9})$

Step 4

Split

$(- \infty, \infty)$ into intervals around the points that could potentially be inflection points.

$(- \infty, - \frac{\sqrt{3}}{3}) \cup (- \frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3}) \cup (\frac{\sqrt{3}}{3}, \infty)$

Step 5

Substitute a value from the interval

$(- \infty, - \frac{\sqrt{3}}{3})$ into the second derivative to determine if it is increasing or decreasing.

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Step 5.1

Replace the variable

$x$ with

$- 0.67735026$ in the expression.

$f'' (- 0.67735026) = 60 {(- 0.67735026)}^{2} - 20$

Step 5.2

Simplify the result.

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Step 5.2.1

Simplify each term.

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Step 5.2.1.1

Raise

$- 0.67735026$ to the power of

$2$ .

$f'' (- 0.67735026) = 60 \cdot 0.45880338 - 20$

Step 5.2.1.2

Multiply

$60$ by

$0.45880338$ .

$f'' (- 0.67735026) = 27.52820323 - 20$

Step 5.2.2

Subtract

$20$ from

$27.52820323$ .

$f'' (- 0.67735026) = 7.52820323$

Step 5.2.3

The final answer is

$7.52820323$ .

$7.52820323$

Step 5.3

$- 0.67735026$ , the second derivative is

$7.52820323$ . Since this is positive, the second derivative is increasing on the interval

$(- \infty, - \frac{\sqrt{3}}{3})$ .

Increasing on

$(- \infty, - \frac{\sqrt{3}}{3})$ since

$f'' (x) > 0$

Increasing on

$(- \infty, - \frac{\sqrt{3}}{3})$ since

$f'' (x) > 0$

Step 6

Substitute a value from the interval

$(- \frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3})$ into the second derivative to determine if it is increasing or decreasing.

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Step 6.1

Replace the variable

$x$ with

$0$ in the expression.

$f'' (0) = 60 {(0)}^{2} - 20$

Step 6.2

Simplify the result.

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Step 6.2.1

Simplify each term.

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Step 6.2.1.1

Raising

$0$ to any positive power yields

$0$ .

$f'' (0) = 60 \cdot 0 - 20$

Step 6.2.1.2

Multiply

$60$ by

$0$ .

$f'' (0) = 0 - 20$

Step 6.2.2

Subtract

$20$ from

$0$ .

$f'' (0) = - 20$

Step 6.2.3

The final answer is

$- 20$ .

$- 20$

Step 6.3

$0$ , the second derivative is

$- 20$ . Since this is negative, the second derivative is decreasing on the interval

$(- \frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3})$

Decreasing on

$(- \frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3})$ since

$f'' (x) < 0$

Decreasing on

$(- \frac{\sqrt{3}}{3}, \frac{\sqrt{3}}{3})$ since

$f'' (x) < 0$

Step 7

Substitute a value from the interval

$(\frac{\sqrt{3}}{3}, \infty)$ into the second derivative to determine if it is increasing or decreasing.

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Step 7.1

Replace the variable

$x$ with

$0.67735026$ in the expression.

$f'' (0.67735026) = 60 {(0.67735026)}^{2} - 20$

Step 7.2

Simplify the result.

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Step 7.2.1

Simplify each term.

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Step 7.2.1.1

Raise

$0.67735026$ to the power of

$2$ .

$f'' (0.67735026) = 60 \cdot 0.45880338 - 20$

Step 7.2.1.2

Multiply

$60$ by

$0.45880338$ .

$f'' (0.67735026) = 27.52820323 - 20$

Step 7.2.2

Subtract

$20$ from

$27.52820323$ .

$f'' (0.67735026) = 7.52820323$

Step 7.2.3

The final answer is

$7.52820323$ .

$7.52820323$

Step 7.3

$0.67735026$ , the second derivative is

$7.52820323$ . Since this is positive, the second derivative is increasing on the interval

$(\frac{\sqrt{3}}{3}, \infty)$ .

Increasing on

$(\frac{\sqrt{3}}{3}, \infty)$ since

$f'' (x) > 0$

Increasing on

$(\frac{\sqrt{3}}{3}, \infty)$ since

$f'' (x) > 0$

Step 8

An inflection point is a point on a curve at which the concavity changes sign from plus to minus or from minus to plus. The inflection points in this case are

$(- \frac{\sqrt{3}}{3}, - \frac{25}{9}), (\frac{\sqrt{3}}{3}, - \frac{25}{9})$ .

$(- \frac{\sqrt{3}}{3}, - \frac{25}{9}), (\frac{\sqrt{3}}{3}, - \frac{25}{9})$

Step 9

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