Calculus Examples
y=5x2+5
Step 1
Set y as a function of x.
f(x)=5x2+5
Step 2
Step 2.1
By the Sum Rule, the derivative of 5x2+5 with respect to x is ddx[5x2]+ddx[5].
ddx[5x2]+ddx[5]
Step 2.2
Evaluate ddx[5x2].
Step 2.2.1
Since 5 is constant with respect to x, the derivative of 5x2 with respect to x is 5ddx[x2].
5ddx[x2]+ddx[5]
Step 2.2.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
5(2x)+ddx[5]
Step 2.2.3
Multiply 2 by 5.
10x+ddx[5]
10x+ddx[5]
Step 2.3
Differentiate using the Constant Rule.
Step 2.3.1
Since 5 is constant with respect to x, the derivative of 5 with respect to x is 0.
10x+0
Step 2.3.2
Add 10x and 0.
10x
10x
10x
Step 3
Step 3.1
Divide each term in 10x=0 by 10.
10x10=010
Step 3.2
Simplify the left side.
Step 3.2.1
Cancel the common factor of 10.
Step 3.2.1.1
Cancel the common factor.
10x10=010
Step 3.2.1.2
Divide x by 1.
x=010
x=010
x=010
Step 3.3
Simplify the right side.
Step 3.3.1
Divide 0 by 10.
x=0
x=0
x=0
Step 4
Step 4.1
Replace the variable x with 0 in the expression.
f(0)=5(0)2+5
Step 4.2
Simplify the result.
Step 4.2.1
Simplify each term.
Step 4.2.1.1
Raising 0 to any positive power yields 0.
f(0)=5⋅0+5
Step 4.2.1.2
Multiply 5 by 0.
f(0)=0+5
f(0)=0+5
Step 4.2.2
Add 0 and 5.
f(0)=5
Step 4.2.3
The final answer is 5.
5
5
5
Step 5
The horizontal tangent line on function f(x)=5x2+5 is y=5.
y=5
Step 6