Calculus Examples
(5x3+21x2-16)÷(x+4)(5x3+21x2−16)÷(x+4)
Step 1
Place the numbers representing the divisor and the dividend into a division-like configuration.
-4−4 | 55 | 2121 | 00 | -16−16 |
Step 2
The first number in the dividend (5)(5) is put into the first position of the result area (below the horizontal line).
-4−4 | 55 | 2121 | 00 | -16−16 |
55 |
Step 3
Multiply the newest entry in the result (5)(5) by the divisor (-4)(−4) and place the result of (-20)(−20) under the next term in the dividend (21)(21).
-4−4 | 55 | 2121 | 00 | -16−16 |
-20−20 | ||||
55 |
Step 4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-4−4 | 55 | 2121 | 00 | -16−16 |
-20−20 | ||||
55 | 11 |
Step 5
Multiply the newest entry in the result (1)(1) by the divisor (-4)(−4) and place the result of (-4)(−4) under the next term in the dividend (0)(0).
-4−4 | 55 | 2121 | 00 | -16−16 |
-20−20 | -4−4 | |||
55 | 11 |
Step 6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-4−4 | 55 | 2121 | 00 | -16−16 |
-20−20 | -4−4 | |||
55 | 11 | -4−4 |
Step 7
Multiply the newest entry in the result (-4)(−4) by the divisor (-4)(−4) and place the result of (16) under the next term in the dividend (-16).
-4 | 5 | 21 | 0 | -16 |
-20 | -4 | 16 | ||
5 | 1 | -4 |
Step 8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
-4 | 5 | 21 | 0 | -16 |
-20 | -4 | 16 | ||
5 | 1 | -4 | 0 |
Step 9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
5x2+1x-4
Step 10
Simplify the quotient polynomial.
5x2+x-4