Calculus Examples

$f (x) = \frac{5 x - 25}{x^{2} - 5 x}$

Step 1

Factor

$5$ out of

$5 x - 25$ .

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Step 1.1

Factor

$5$ out of

$5 x$ .

$f (x) = \frac{5 (x) - 25}{x^{2} - 5 x}$

Step 1.2

Factor

$5$ out of

$- 25$ .

$f (x) = \frac{5 x + 5 \cdot - 5}{x^{2} - 5 x}$

Step 1.3

Factor

$5$ out of

$5 x + 5 \cdot - 5$ .

$f (x) = \frac{5 (x - 5)}{x^{2} - 5 x}$

Step 2

Factor

$x$ out of

$x^{2} - 5 x$ .

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Step 2.1

Factor

$x$ out of

$x^{2}$ .

$f (x) = \frac{5 (x - 5)}{x \cdot x - 5 x}$

Step 2.2

Factor

$x$ out of

$- 5 x$ .

$f (x) = \frac{5 (x - 5)}{x \cdot x + x \cdot - 5}$

Step 2.3

Factor

$x$ out of

$x \cdot x + x \cdot - 5$ .

$f (x) = \frac{5 (x - 5)}{x (x - 5)}$

Step 3

Cancel the common factor of

$x - 5$ .

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Step 3.1

Cancel the common factor.

$f (x) = \frac{5 (x - 5)}{x (x - 5)}$

Step 3.2

Rewrite the expression.

$f (x) = \frac{5}{x}$

Step 4

To find the holes in the graph, look at the denominator factors that were cancelled.

$x - 5$

Step 5

To find the coordinates of the holes, set each factor that was cancelled equal to

$0$ , solve, and substitute back in to

$\frac{5}{x}$ .

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Step 5.1

Set

$x - 5$ equal to

$0$ .

$x - 5 = 0$

Step 5.2

Add

$5$ to both sides of the equation.

$x = 5$

Step 5.3

Substitute

$5$ for

$x$ in

$\frac{5}{x}$ and simplify.

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Step 5.3.1

Substitute

$5$ for

$x$ to find the

$y$ coordinate of the hole.

$\frac{5}{5}$

Step 5.3.2

Divide

$5$ by

$5$ .

$1$

Step 5.4

The holes in the graph are the points where any of the cancelled factors are equal to

$0$ .

$(5, 1)$

Step 6

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