Basic Math Examples

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\begin{array}{r} h = & 5 \\ r = & 1 \end{array}

$\begin{array}{r} h = & 5 \\ r = & 1 \end{array}$

Step 1

The volume of a cone is equal to

\frac{1}{3}

$\frac{1}{3}$ times the area of the base

π r^{2}

$π r^{2}$ times the height

h

$h$ .

\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)

$\frac{1}{3} \cdot π \cdot {(r a d i u s)}^{2} \cdot (h e i g h t)$

Step 2

Substitute the values of the radius

r = 1

$r = 1$ and height

h = 5

$h = 5$ into the formula to find the volume of the cone. Pi

π

$π$ is approximately equal to

3.14

$3.14$ .

\frac{1}{3} \cdot π \cdot 1^{2} \cdot 5

$\frac{1}{3} \cdot π \cdot 1^{2} \cdot 5$

Step 3

Combine

\frac{1}{3}

$\frac{1}{3}$ and

π

$π$ .

\frac{π}{3} \cdot 1^{2} \cdot 5

$\frac{π}{3} \cdot 1^{2} \cdot 5$

Step 4

Simplify the expression.

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Step 4.1

One to any power is one.

\frac{π}{3} \cdot 1 \cdot 5

$\frac{π}{3} \cdot 1 \cdot 5$

Step 4.2

Multiply

\frac{π}{3}

$\frac{π}{3}$ by

1

$1$ .

\frac{π}{3} \cdot 5

$\frac{π}{3} \cdot 5$

\frac{π}{3} \cdot 5

$\frac{π}{3} \cdot 5$

Step 5

Combine

\frac{π}{3}

$\frac{π}{3}$ and

5

$5$ .

\frac{π \cdot 5}{3}

$\frac{π \cdot 5}{3}$

Step 6

Move

5

$5$ to the left of

π

$π$ .

\frac{5 π}{3}

$\frac{5 π}{3}$

Step 7

The result can be shown in multiple forms.

Exact Form:

\frac{5 π}{3}

$\frac{5 π}{3}$

Decimal Form:

5.23598775 \dots

$5.23598775 \dots$

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