Basic Math Examples

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\begin{matrix} b_{1} = & 10 b_{2} = & 2 h = & 1 \end{matrix}

$\begin{array}{r} b_{1} = & 10 \\ b_{2} = & 2 \\ h = & 1 \end{array}$

Step 1

The area of a trapezoid is equal to

\frac{1}{2}

$\frac{1}{2}$ times the height times the sum of the bases

b_{1} + b_{2}

$b_{1} + b_{2}$ .

\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

h = 1

$h = 1$ and bases (

b_{1} = 10

$b_{1} = 10$ and

b_{2} = 2

$b_{2} = 2$ ) into the formula for the area of a trapezoid.

\frac{1}{2} \cdot 1 \cdot (10 + 2)

$\frac{1}{2} \cdot 1 \cdot (10 + 2)$

Step 3

Simplify the expression.

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Step 3.1

Multiply

\frac{1}{2}

$\frac{1}{2}$ by

1

$1$ .

\frac{1}{2} \cdot (10 + 2)

$\frac{1}{2} \cdot (10 + 2)$

Step 3.2

Add

10

$10$ and

2

$2$ .

\frac{1}{2} \cdot 12

$\frac{1}{2} \cdot 12$

\frac{1}{2} \cdot 12

$\frac{1}{2} \cdot 12$

Step 4

Cancel the common factor of

2

$2$ .

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Step 4.1

Factor

2

$2$ out of

12

$12$ .

\frac{1}{2} \cdot (2 (6))

$\frac{1}{2} \cdot (2 (6))$

Step 4.2

Cancel the common factor.

$\frac{1}{2} \cdot (2 \cdot 6)$

Step 4.3

Rewrite the expression.

$6$

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