Basic Math Examples

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\begin{matrix} b_{1} = & 1 b_{2} = & 6 h = & 2 \end{matrix}

$\begin{array}{r} b_{1} = & 1 \\ b_{2} = & 6 \\ h = & 2 \end{array}$

Step 1

The area of a trapezoid is equal to

$\frac{1}{2}$ times the height times the sum of the bases

$b_{1} + b_{2}$ .

$\frac{1}{2} \cdot (h e i g h t) \cdot (b_{1} + b_{2})$

Step 2

Substitute the values of the height

$h = 2$ and bases (

$b_{1} = 1$ and

$b_{2} = 6$ ) into the formula for the area of a trapezoid.

$\frac{1}{2} \cdot 2 \cdot (1 + 6)$

Step 3

Cancel the common factor of

$2$ .

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Step 3.1

Cancel the common factor.

$\frac{1}{2} \cdot 2 \cdot (1 + 6)$

Step 3.2

Rewrite the expression.

$1 \cdot (1 + 6)$

Step 4

Simplify the expression.

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Step 4.1

Multiply

$1 + 6$ by

$1$ .

$1 + 6$

Step 4.2

Add

$1$ and

$6$ .

$7$

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