Algebra Examples

$\begin{array}{c} x & q (x) \\ 1 & 5 \\ 9 & 165 \\ 2 & 11 \\ 8 & 131 \\ 3 & 21 \end{array}$

Step 1

Check if the function rule is linear.

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Step 1.1

To find if the table follows a function rule, check to see if the values follow the linear form $y = a x + b$ .

$y = a x + b$

Step 1.2

Build a set of equations from the table such that $q (x) = a x + b$ .

$5 = a (1) + b 165 = a (9) + b 11 = a (2) + b 131 = a (8) + b 21 = a (3) + b$

Step 1.3

Calculate the values of $a$ and $b$ .

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Step 1.3.1

Solve for $a$ in $5 = a + b$ .

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Step 1.3.1.1

Rewrite the equation as $a + b = 5$ .

$a + b = 5$

$165 = a (9) + b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.1.2

Subtract $b$ from both sides of the equation.

$a = 5 - b$

$165 = a (9) + b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

$a = 5 - b$

$165 = a (9) + b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2

Replace all occurrences of $a$ with $5 - b$ in each equation.

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Step 1.3.2.1

Replace all occurrences of $a$ in $165 = a (9) + b$ with $5 - b$ .

$165 = (5 - b) (9) + b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.2

Simplify the right side.

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Step 1.3.2.2.1

Simplify $(5 - b) (9) + b$ .

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Step 1.3.2.2.1.1

Simplify each term.

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Step 1.3.2.2.1.1.1

Apply the distributive property.

$165 = 5 \cdot 9 - b \cdot 9 + b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.2.1.1.2

Multiply $5$ by $9$ .

$165 = 45 - b \cdot 9 + b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.2.1.1.3

Multiply $9$ by $- 1$ .

$165 = 45 - 9 b + b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

$165 = 45 - 9 b + b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.2.1.2

Add $- 9 b$ and $b$ .

$165 = 45 - 8 b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

$165 = 45 - 8 b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

$165 = 45 - 8 b$

$a = 5 - b$

$11 = a (2) + b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.3

Replace all occurrences of $a$ in $11 = a (2) + b$ with $5 - b$ .

$11 = (5 - b) (2) + b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.4

Simplify the right side.

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Step 1.3.2.4.1

Simplify $(5 - b) (2) + b$ .

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Step 1.3.2.4.1.1

Simplify each term.

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Step 1.3.2.4.1.1.1

Apply the distributive property.

$11 = 5 \cdot 2 - b \cdot 2 + b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.4.1.1.2

Multiply $5$ by $2$ .

$11 = 10 - b \cdot 2 + b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.4.1.1.3

Multiply $2$ by $- 1$ .

$11 = 10 - 2 b + b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

$11 = 10 - 2 b + b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.4.1.2

Add $- 2 b$ and $b$ .

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = a (8) + b$

$21 = a (3) + b$

Step 1.3.2.5

Replace all occurrences of $a$ in $131 = a (8) + b$ with $5 - b$ .

$131 = (5 - b) (8) + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

Step 1.3.2.6

Simplify the right side.

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Step 1.3.2.6.1

Simplify $(5 - b) (8) + b$ .

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Step 1.3.2.6.1.1

Simplify each term.

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Step 1.3.2.6.1.1.1

Apply the distributive property.

$131 = 5 \cdot 8 - b \cdot 8 + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

Step 1.3.2.6.1.1.2

Multiply $5$ by $8$ .

$131 = 40 - b \cdot 8 + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

Step 1.3.2.6.1.1.3

Multiply $8$ by $- 1$ .

$131 = 40 - 8 b + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

$131 = 40 - 8 b + b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

Step 1.3.2.6.1.2

Add $- 8 b$ and $b$ .

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = a (3) + b$

Step 1.3.2.7

Replace all occurrences of $a$ in $21 = a (3) + b$ with $5 - b$ .

$21 = (5 - b) (3) + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.2.8

Simplify the right side.

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Step 1.3.2.8.1

Simplify $(5 - b) (3) + b$ .

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Step 1.3.2.8.1.1

Simplify each term.

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Step 1.3.2.8.1.1.1

Apply the distributive property.

$21 = 5 \cdot 3 - b \cdot 3 + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.2.8.1.1.2

Multiply $5$ by $3$ .

$21 = 15 - b \cdot 3 + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.2.8.1.1.3

Multiply $3$ by $- 1$ .

$21 = 15 - 3 b + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = 15 - 3 b + b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.2.8.1.2

Add $- 3 b$ and $b$ .

$21 = 15 - 2 b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = 15 - 2 b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = 15 - 2 b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$21 = 15 - 2 b$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3

Solve for $b$ in $21 = 15 - 2 b$ .

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Step 1.3.3.1

Rewrite the equation as $15 - 2 b = 21$ .

$15 - 2 b = 21$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.2

Move all terms not containing $b$ to the right side of the equation.

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Step 1.3.3.2.1

Subtract $15$ from both sides of the equation.

$- 2 b = 21 - 15$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.2.2

Subtract $15$ from $21$ .

$- 2 b = 6$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$- 2 b = 6$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.3

Divide each term in $- 2 b = 6$ by $- 2$ and simplify.

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Step 1.3.3.3.1

Divide each term in $- 2 b = 6$ by $- 2$ .

$\frac{- 2 b}{- 2} = \frac{6}{- 2}$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.3.2

Simplify the left side.

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Step 1.3.3.3.2.1

Cancel the common factor of $- 2$ .

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Step 1.3.3.3.2.1.1

Cancel the common factor.

$\frac{- 2 b}{- 2} = \frac{6}{- 2}$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.3.2.1.2

Divide $b$ by $1$ .

$b = \frac{6}{- 2}$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$b = \frac{6}{- 2}$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$b = \frac{6}{- 2}$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.3.3.3

Simplify the right side.

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Step 1.3.3.3.3.1

Divide $6$ by $- 2$ .

$b = - 3$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$b = - 3$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$b = - 3$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$b = - 3$

$131 = 40 - 7 b$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4

Replace all occurrences of $b$ with $- 3$ in each equation.

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Step 1.3.4.1

Replace all occurrences of $b$ in $131 = 40 - 7 b$ with $- 3$ .

$131 = 40 - 7 \cdot - 3$

$b = - 3$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.2

Simplify the right side.

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Step 1.3.4.2.1

Simplify $40 - 7 \cdot - 3$ .

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Step 1.3.4.2.1.1

Multiply $- 7$ by $- 3$ .

$131 = 40 + 21$

$b = - 3$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.2.1.2

Add $40$ and $21$ .

$131 = 61$

$b = - 3$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = 61$

$b = - 3$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

$131 = 61$

$b = - 3$

$11 = 10 - b$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.3

Replace all occurrences of $b$ in $11 = 10 - b$ with $- 3$ .

$11 = 10 - (- 3)$

$131 = 61$

$b = - 3$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.4

Simplify the right side.

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Step 1.3.4.4.1

Simplify $10 - (- 3)$ .

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Step 1.3.4.4.1.1

Multiply $- 1$ by $- 3$ .

$11 = 10 + 3$

$131 = 61$

$b = - 3$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.4.1.2

Add $10$ and $3$ .

$11 = 13$

$131 = 61$

$b = - 3$

$165 = 45 - 8 b$

$a = 5 - b$

$11 = 13$

$131 = 61$

$b = - 3$

$165 = 45 - 8 b$

$a = 5 - b$

$11 = 13$

$131 = 61$

$b = - 3$

$165 = 45 - 8 b$

$a = 5 - b$

Step 1.3.4.5

Replace all occurrences of $b$ in $165 = 45 - 8 b$ with $- 3$ .

$165 = 45 - 8 \cdot - 3$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 5 - b$

Step 1.3.4.6

Simplify the right side.

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Step 1.3.4.6.1

Simplify $45 - 8 \cdot - 3$ .

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Step 1.3.4.6.1.1

Multiply $- 8$ by $- 3$ .

$165 = 45 + 24$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 5 - b$

Step 1.3.4.6.1.2

Add $45$ and $24$ .

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 5 - b$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 5 - b$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 5 - b$

Step 1.3.4.7

Replace all occurrences of $b$ in $a = 5 - b$ with $- 3$ .

$a = 5 - (- 3)$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

Step 1.3.4.8

Simplify the right side.

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Step 1.3.4.8.1

Simplify $5 - (- 3)$ .

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Step 1.3.4.8.1.1

Multiply $- 1$ by $- 3$ .

$a = 5 + 3$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

Step 1.3.4.8.1.2

Add $5$ and $3$ .

$a = 8$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 8$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 8$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

$a = 8$

$165 = 69$

$11 = 13$

$131 = 61$

$b = - 3$

Step 1.3.5

Since $165 = 69$ is not true, there is no solution.

No solution

Step 1.4

Since $y \neq q (x)$ for the corresponding $x$ values, the function is not linear.

The function is not linear

Step 2

Check if the function rule is quadratic.

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Step 2.1

To find if the table follows a function rule, check whether the function rule could follow the form $y = a x^{2} + b x + c$ .

$y = a x^{2} + b x + c$

Step 2.2

Build a set of $3$ equations from the table such that $q (x) = a x^{2} + b x + c$ .

Step 2.3

Calculate the values of $a$ , $b$ , and $c$ .

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Step 2.3.1

Solve for $a$ in $5 = a + b + c$ .

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Step 2.3.1.1

Rewrite the equation as $a + b + c = 5$ .

$a + b + c = 5$

$165 = a \cdot 9^{2} + b (9) + c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.1.2

Move all terms not containing $a$ to the right side of the equation.

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Step 2.3.1.2.1

Subtract $b$ from both sides of the equation.

$a + c = 5 - b$

$165 = a \cdot 9^{2} + b (9) + c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.1.2.2

Subtract $c$ from both sides of the equation.

$a = 5 - b - c$

$165 = a \cdot 9^{2} + b (9) + c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$a = 5 - b - c$

$165 = a \cdot 9^{2} + b (9) + c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$a = 5 - b - c$

$165 = a \cdot 9^{2} + b (9) + c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2

Replace all occurrences of $a$ with $5 - b - c$ in each equation.

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Step 2.3.2.1

Replace all occurrences of $a$ in $165 = a \cdot 9^{2} + b (9) + c$ with $5 - b - c$ .

$165 = (5 - b - c) \cdot 9^{2} + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2

Simplify the right side.

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Step 2.3.2.2.1

Simplify $(5 - b - c) \cdot 9^{2} + b (9) + c$ .

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Step 2.3.2.2.1.1

Simplify each term.

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Step 2.3.2.2.1.1.1

Raise $9$ to the power of $2$ .

$165 = (5 - b - c) \cdot 81 + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.1.2

Apply the distributive property.

$165 = 5 \cdot 81 - b \cdot 81 - c \cdot 81 + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.1.3

Simplify.

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Step 2.3.2.2.1.1.3.1

Multiply $5$ by $81$ .

$165 = 405 - b \cdot 81 - c \cdot 81 + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.1.3.2

Multiply $81$ by $- 1$ .

$165 = 405 - 81 b - c \cdot 81 + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.1.3.3

Multiply $81$ by $- 1$ .

$165 = 405 - 81 b - 81 c + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$165 = 405 - 81 b - 81 c + b (9) + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.1.4

Move $9$ to the left of $b$ .

$165 = 405 - 81 b - 81 c + 9 b + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$165 = 405 - 81 b - 81 c + 9 b + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.2

Simplify by adding terms.

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Step 2.3.2.2.1.2.1

Add $- 81 b$ and $9 b$ .

$165 = 405 - 72 b - 81 c + c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.2.1.2.2

Add $- 81 c$ and $c$ .

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = a \cdot 2^{2} + b (2) + c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.3

Replace all occurrences of $a$ in $11 = a \cdot 2^{2} + b (2) + c$ with $5 - b - c$ .

$11 = (5 - b - c) \cdot 2^{2} + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4

Simplify the right side.

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Step 2.3.2.4.1

Simplify $(5 - b - c) \cdot 2^{2} + b (2) + c$ .

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Step 2.3.2.4.1.1

Simplify each term.

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Step 2.3.2.4.1.1.1

Raise $2$ to the power of $2$ .

$11 = (5 - b - c) \cdot 4 + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.1.2

Apply the distributive property.

$11 = 5 \cdot 4 - b \cdot 4 - c \cdot 4 + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.1.3

Simplify.

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Step 2.3.2.4.1.1.3.1

Multiply $5$ by $4$ .

$11 = 20 - b \cdot 4 - c \cdot 4 + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.1.3.2

Multiply $4$ by $- 1$ .

$11 = 20 - 4 b - c \cdot 4 + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.1.3.3

Multiply $4$ by $- 1$ .

$11 = 20 - 4 b - 4 c + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$11 = 20 - 4 b - 4 c + b (2) + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.1.4

Move $2$ to the left of $b$ .

$11 = 20 - 4 b - 4 c + 2 b + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$11 = 20 - 4 b - 4 c + 2 b + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.2

Simplify by adding terms.

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Step 2.3.2.4.1.2.1

Add $- 4 b$ and $2 b$ .

$11 = 20 - 2 b - 4 c + c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.4.1.2.2

Add $- 4 c$ and $c$ .

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = a \cdot 8^{2} + b (8) + c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.5

Replace all occurrences of $a$ in $131 = a \cdot 8^{2} + b (8) + c$ with $5 - b - c$ .

$131 = (5 - b - c) \cdot 8^{2} + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6

Simplify the right side.

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Step 2.3.2.6.1

Simplify $(5 - b - c) \cdot 8^{2} + b (8) + c$ .

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Step 2.3.2.6.1.1

Simplify each term.

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Step 2.3.2.6.1.1.1

Raise $8$ to the power of $2$ .

$131 = (5 - b - c) \cdot 64 + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.1.2

Apply the distributive property.

$131 = 5 \cdot 64 - b \cdot 64 - c \cdot 64 + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.1.3

Simplify.

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Step 2.3.2.6.1.1.3.1

Multiply $5$ by $64$ .

$131 = 320 - b \cdot 64 - c \cdot 64 + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.1.3.2

Multiply $64$ by $- 1$ .

$131 = 320 - 64 b - c \cdot 64 + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.1.3.3

Multiply $64$ by $- 1$ .

$131 = 320 - 64 b - 64 c + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

$131 = 320 - 64 b - 64 c + b (8) + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.1.4

Move $8$ to the left of $b$ .

$131 = 320 - 64 b - 64 c + 8 b + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

$131 = 320 - 64 b - 64 c + 8 b + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.2

Simplify by adding terms.

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Step 2.3.2.6.1.2.1

Add $- 64 b$ and $8 b$ .

$131 = 320 - 56 b - 64 c + c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.6.1.2.2

Add $- 64 c$ and $c$ .

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = a \cdot 3^{2} + b (3) + c$

Step 2.3.2.7

Replace all occurrences of $a$ in $21 = a \cdot 3^{2} + b (3) + c$ with $5 - b - c$ .

$21 = (5 - b - c) \cdot 3^{2} + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8

Simplify the right side.

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Step 2.3.2.8.1

Simplify $(5 - b - c) \cdot 3^{2} + b (3) + c$ .

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Step 2.3.2.8.1.1

Simplify each term.

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Step 2.3.2.8.1.1.1

Raise $3$ to the power of $2$ .

$21 = (5 - b - c) \cdot 9 + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.1.2

Apply the distributive property.

$21 = 5 \cdot 9 - b \cdot 9 - c \cdot 9 + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.1.3

Simplify.

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Step 2.3.2.8.1.1.3.1

Multiply $5$ by $9$ .

$21 = 45 - b \cdot 9 - c \cdot 9 + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.1.3.2

Multiply $9$ by $- 1$ .

$21 = 45 - 9 b - c \cdot 9 + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.1.3.3

Multiply $9$ by $- 1$ .

$21 = 45 - 9 b - 9 c + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 9 b - 9 c + b (3) + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.1.4

Move $3$ to the left of $b$ .

$21 = 45 - 9 b - 9 c + 3 b + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 9 b - 9 c + 3 b + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.2

Simplify by adding terms.

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Step 2.3.2.8.1.2.1

Add $- 9 b$ and $3 b$ .

$21 = 45 - 6 b - 9 c + c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.2.8.1.2.2

Add $- 9 c$ and $c$ .

$21 = 45 - 6 b - 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 6 b - 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 6 b - 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 6 b - 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$21 = 45 - 6 b - 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3

Solve for $b$ in $21 = 45 - 6 b - 8 c$ .

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Step 2.3.3.1

Rewrite the equation as $45 - 6 b - 8 c = 21$ .

$45 - 6 b - 8 c = 21$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.2

Move all terms not containing $b$ to the right side of the equation.

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Step 2.3.3.2.1

Subtract $45$ from both sides of the equation.

$- 6 b - 8 c = 21 - 45$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.2.2

Add $8 c$ to both sides of the equation.

$- 6 b = 21 - 45 + 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.2.3

Subtract $45$ from $21$ .

$- 6 b = - 24 + 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$- 6 b = - 24 + 8 c$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3

Divide each term in $- 6 b = - 24 + 8 c$ by $- 6$ and simplify.

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Step 2.3.3.3.1

Divide each term in $- 6 b = - 24 + 8 c$ by $- 6$ .

$\frac{- 6 b}{- 6} = \frac{- 24}{- 6} + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.2

Simplify the left side.

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Step 2.3.3.3.2.1

Cancel the common factor of $- 6$ .

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Step 2.3.3.3.2.1.1

Cancel the common factor.

$\frac{- 6 b}{- 6} = \frac{- 24}{- 6} + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.2.1.2

Divide $b$ by $1$ .

$b = \frac{- 24}{- 6} + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = \frac{- 24}{- 6} + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = \frac{- 24}{- 6} + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3

Simplify the right side.

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Step 2.3.3.3.3.1

Simplify each term.

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Step 2.3.3.3.3.1.1

Divide $- 24$ by $- 6$ .

$b = 4 + \frac{8 c}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3.1.2

Cancel the common factor of $8$ and $- 6$ .

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Step 2.3.3.3.3.1.2.1

Factor $2$ out of $8 c$ .

$b = 4 + \frac{2 (4 c)}{- 6}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3.1.2.2

Cancel the common factors.

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Step 2.3.3.3.3.1.2.2.1

Factor $2$ out of $- 6$ .

$b = 4 + \frac{2 (4 c)}{2 (- 3)}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3.1.2.2.2

Cancel the common factor.

$b = 4 + \frac{2 (4 c)}{2 \cdot - 3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3.1.2.2.3

Rewrite the expression.

$b = 4 + \frac{4 c}{- 3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 + \frac{4 c}{- 3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 + \frac{4 c}{- 3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.3.3.3.1.3

Move the negative in front of the fraction.

$b = 4 - \frac{4 c}{3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 - \frac{4 c}{3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 - \frac{4 c}{3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 - \frac{4 c}{3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$b = 4 - \frac{4 c}{3}$

$131 = 320 - 56 b - 63 c$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4

Replace all occurrences of $b$ with $4 - \frac{4 c}{3}$ in each equation.

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Step 2.3.4.1

Replace all occurrences of $b$ in $131 = 320 - 56 b - 63 c$ with $4 - \frac{4 c}{3}$ .

$131 = 320 - 56 (4 - \frac{4 c}{3}) - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2

Simplify the right side.

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Step 2.3.4.2.1

Simplify $320 - 56 (4 - \frac{4 c}{3}) - 63 c$ .

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Step 2.3.4.2.1.1

Simplify each term.

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Step 2.3.4.2.1.1.1

Apply the distributive property.

$131 = 320 - 56 \cdot 4 - 56 (- \frac{4 c}{3}) - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.1.2

Multiply $- 56$ by $4$ .

$131 = 320 - 224 - 56 (- \frac{4 c}{3}) - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.1.3

Multiply $- 56 (- \frac{4 c}{3})$ .

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Step 2.3.4.2.1.1.3.1

Multiply $- 1$ by $- 56$ .

$131 = 320 - 224 + 56 (\frac{4 c}{3}) - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.1.3.2

Combine $56$ and $\frac{4 c}{3}$ .

$131 = 320 - 224 + \frac{56 (4 c)}{3} - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.1.3.3

Multiply $4$ by $56$ .

$131 = 320 - 224 + \frac{224 c}{3} - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 320 - 224 + \frac{224 c}{3} - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 320 - 224 + \frac{224 c}{3} - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.2

Subtract $224$ from $320$ .

$131 = 96 + \frac{224 c}{3} - 63 c$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.3

To write $- 63 c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$131 = 96 + \frac{224 c}{3} - 63 c \cdot \frac{3}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.4

Simplify terms.

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Step 2.3.4.2.1.4.1

Combine $- 63 c$ and $\frac{3}{3}$ .

$131 = 96 + \frac{224 c}{3} + \frac{- 63 c \cdot 3}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.4.2

Combine the numerators over the common denominator.

$131 = 96 + \frac{224 c - 63 c \cdot 3}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 96 + \frac{224 c - 63 c \cdot 3}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5

Simplify the numerator.

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Step 2.3.4.2.1.5.1

Factor $7 c$ out of $224 c - 63 c \cdot 3$ .

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Step 2.3.4.2.1.5.1.1

Factor $7 c$ out of $224 c$ .

$131 = 96 + \frac{7 c (32) - 63 c \cdot 3}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5.1.2

Factor $7 c$ out of $- 63 c \cdot 3$ .

$131 = 96 + \frac{7 c (32) + 7 c (- 9 \cdot 3)}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5.1.3

Factor $7 c$ out of $7 c (32) + 7 c (- 9 \cdot 3)$ .

$131 = 96 + \frac{7 c (32 - 9 \cdot 3)}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 96 + \frac{7 c (32 - 9 \cdot 3)}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5.2

Multiply $- 9$ by $3$ .

$131 = 96 + \frac{7 c (32 - 27)}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5.3

Subtract $27$ from $32$ .

$131 = 96 + \frac{7 c \cdot 5}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.2.1.5.4

Multiply $5$ by $7$ .

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 20 - 2 b - 3 c$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.3

Replace all occurrences of $b$ in $11 = 20 - 2 b - 3 c$ with $4 - \frac{4 c}{3}$ .

$11 = 20 - 2 (4 - \frac{4 c}{3}) - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4

Simplify the right side.

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Step 2.3.4.4.1

Simplify $20 - 2 (4 - \frac{4 c}{3}) - 3 c$ .

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Step 2.3.4.4.1.1

Simplify each term.

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Step 2.3.4.4.1.1.1

Apply the distributive property.

$11 = 20 - 2 \cdot 4 - 2 (- \frac{4 c}{3}) - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.1.2

Multiply $- 2$ by $4$ .

$11 = 20 - 8 - 2 (- \frac{4 c}{3}) - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.1.3

Multiply $- 2 (- \frac{4 c}{3})$ .

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Step 2.3.4.4.1.1.3.1

Multiply $- 1$ by $- 2$ .

$11 = 20 - 8 + 2 (\frac{4 c}{3}) - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.1.3.2

Combine $2$ and $\frac{4 c}{3}$ .

$11 = 20 - 8 + \frac{2 (4 c)}{3} - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.1.3.3

Multiply $4$ by $2$ .

$11 = 20 - 8 + \frac{8 c}{3} - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 20 - 8 + \frac{8 c}{3} - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 20 - 8 + \frac{8 c}{3} - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.2

Subtract $8$ from $20$ .

$11 = 12 + \frac{8 c}{3} - 3 c$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.3

To write $- 3 c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$11 = 12 + \frac{8 c}{3} - 3 c \cdot \frac{3}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.4

Simplify terms.

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Step 2.3.4.4.1.4.1

Combine $- 3 c$ and $\frac{3}{3}$ .

$11 = 12 + \frac{8 c}{3} + \frac{- 3 c \cdot 3}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.4.2

Combine the numerators over the common denominator.

$11 = 12 + \frac{8 c - 3 c \cdot 3}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 + \frac{8 c - 3 c \cdot 3}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5

Simplify each term.

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Step 2.3.4.4.1.5.1

Simplify the numerator.

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Step 2.3.4.4.1.5.1.1

Factor $c$ out of $8 c - 3 c \cdot 3$ .

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Step 2.3.4.4.1.5.1.1.1

Factor $c$ out of $8 c$ .

$11 = 12 + \frac{c \cdot 8 - 3 c \cdot 3}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.1.1.2

Factor $c$ out of $- 3 c \cdot 3$ .

$11 = 12 + \frac{c \cdot 8 + c (- 3 \cdot 3)}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.1.1.3

Factor $c$ out of $c \cdot 8 + c (- 3 \cdot 3)$ .

$11 = 12 + \frac{c (8 - 3 \cdot 3)}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 + \frac{c (8 - 3 \cdot 3)}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.1.2

Multiply $- 3$ by $3$ .

$11 = 12 + \frac{c (8 - 9)}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.1.3

Subtract $9$ from $8$ .

$11 = 12 + \frac{c \cdot - 1}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 + \frac{c \cdot - 1}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.2

Move $- 1$ to the left of $c$ .

$11 = 12 + \frac{- 1 \cdot c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.4.1.5.3

Move the negative in front of the fraction.

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$165 = 405 - 72 b - 80 c$

$a = 5 - b - c$

Step 2.3.4.5

Replace all occurrences of $b$ in $165 = 405 - 72 b - 80 c$ with $4 - \frac{4 c}{3}$ .

$165 = 405 - 72 (4 - \frac{4 c}{3}) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6

Simplify the right side.

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Step 2.3.4.6.1

Simplify $405 - 72 (4 - \frac{4 c}{3}) - 80 c$ .

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Step 2.3.4.6.1.1

Simplify each term.

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Step 2.3.4.6.1.1.1

Apply the distributive property.

$165 = 405 - 72 \cdot 4 - 72 (- \frac{4 c}{3}) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.2

Multiply $- 72$ by $4$ .

$165 = 405 - 288 - 72 (- \frac{4 c}{3}) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.3

Cancel the common factor of $3$ .

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Step 2.3.4.6.1.1.3.1

Move the leading negative in $- \frac{4 c}{3}$ into the numerator.

$165 = 405 - 288 - 72 \frac{- 4 c}{3} - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.3.2

Factor $3$ out of $- 72$ .

$165 = 405 - 288 + 3 (- 24) (\frac{- 4 c}{3}) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.3.3

Cancel the common factor.

$165 = 405 - 288 + 3 \cdot (- 24 \frac{- 4 c}{3}) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.3.4

Rewrite the expression.

$165 = 405 - 288 - 24 (- 4 c) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

$165 = 405 - 288 - 24 (- 4 c) - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.1.4

Multiply $- 4$ by $- 24$ .

$165 = 405 - 288 + 96 c - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

$165 = 405 - 288 + 96 c - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.2

Simplify by adding terms.

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Step 2.3.4.6.1.2.1

Subtract $288$ from $405$ .

$165 = 117 + 96 c - 80 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.6.1.2.2

Subtract $80 c$ from $96 c$ .

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - b - c$

Step 2.3.4.7

Replace all occurrences of $b$ in $a = 5 - b - c$ with $4 - \frac{4 c}{3}$ .

$a = 5 - (4 - \frac{4 c}{3}) - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8

Simplify the right side.

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Step 2.3.4.8.1

Simplify $5 - (4 - \frac{4 c}{3}) - c$ .

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Step 2.3.4.8.1.1

Simplify each term.

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Step 2.3.4.8.1.1.1

Apply the distributive property.

$a = 5 - 1 \cdot 4 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.1.2

Multiply $- 1$ by $4$ .

$a = 5 - 4 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.1.3

Multiply $- - \frac{4 c}{3}$ .

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Step 2.3.4.8.1.1.3.1

Multiply $- 1$ by $- 1$ .

$a = 5 - 4 + 1 (\frac{4 c}{3}) - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.1.3.2

Multiply $\frac{4 c}{3}$ by $1$ .

$a = 5 - 4 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - 4 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 5 - 4 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.2

Subtract $4$ from $5$ .

$a = 1 + \frac{4 c}{3} - c$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.3

To write $- c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$a = 1 + \frac{4 c}{3} - c \cdot \frac{3}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.4

Simplify terms.

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Step 2.3.4.8.1.4.1

Combine $- c$ and $\frac{3}{3}$ .

$a = 1 + \frac{4 c}{3} + \frac{- c \cdot 3}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.4.2

Combine the numerators over the common denominator.

$a = 1 + \frac{4 c - c \cdot 3}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{4 c - c \cdot 3}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5

Simplify each term.

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Step 2.3.4.8.1.5.1

Simplify the numerator.

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Step 2.3.4.8.1.5.1.1

Factor $c$ out of $4 c - c \cdot 3$ .

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Step 2.3.4.8.1.5.1.1.1

Factor $c$ out of $4 c$ .

$a = 1 + \frac{c \cdot 4 - c \cdot 3}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5.1.1.2

Factor $c$ out of $- c \cdot 3$ .

$a = 1 + \frac{c \cdot 4 + c (- 1 \cdot 3)}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5.1.1.3

Factor $c$ out of $c \cdot 4 + c (- 1 \cdot 3)$ .

$a = 1 + \frac{c (4 - 1 \cdot 3)}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c (4 - 1 \cdot 3)}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5.1.2

Multiply $- 1$ by $3$ .

$a = 1 + \frac{c (4 - 3)}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5.1.3

Subtract $3$ from $4$ .

$a = 1 + \frac{c \cdot 1}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c \cdot 1}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.4.8.1.5.2

Multiply $c$ by $1$ .

$a = 1 + \frac{c}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 1 + \frac{c}{3}$

$165 = 117 + 16 c$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5

Solve for $c$ in $165 = 117 + 16 c$ .

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Step 2.3.5.1

Rewrite the equation as $117 + 16 c = 165$ .

$117 + 16 c = 165$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.2

Move all terms not containing $c$ to the right side of the equation.

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Step 2.3.5.2.1

Subtract $117$ from both sides of the equation.

$16 c = 165 - 117$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.2.2

Subtract $117$ from $165$ .

$16 c = 48$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$16 c = 48$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.3

Divide each term in $16 c = 48$ by $16$ and simplify.

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Step 2.3.5.3.1

Divide each term in $16 c = 48$ by $16$ .

$\frac{16 c}{16} = \frac{48}{16}$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.3.2

Simplify the left side.

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Step 2.3.5.3.2.1

Cancel the common factor of $16$ .

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Step 2.3.5.3.2.1.1

Cancel the common factor.

$\frac{16 c}{16} = \frac{48}{16}$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.3.2.1.2

Divide $c$ by $1$ .

$c = \frac{48}{16}$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$c = \frac{48}{16}$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$c = \frac{48}{16}$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.5.3.3

Simplify the right side.

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Step 2.3.5.3.3.1

Divide $48$ by $16$ .

$c = 3$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$c = 3$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$c = 3$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$c = 3$

$a = 1 + \frac{c}{3}$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6

Replace all occurrences of $c$ with $3$ in each equation.

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Step 2.3.6.1

Replace all occurrences of $c$ in $a = 1 + \frac{c}{3}$ with $3$ .

$a = 1 + \frac{3}{3}$

$c = 3$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.2

Simplify the right side.

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Step 2.3.6.2.1

Simplify $1 + \frac{3}{3}$ .

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Step 2.3.6.2.1.1

Divide $3$ by $3$ .

$a = 1 + 1$

$c = 3$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.2.1.2

Add $1$ and $1$ .

$a = 2$

$c = 3$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 2$

$c = 3$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$a = 2$

$c = 3$

$11 = 12 - \frac{c}{3}$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.3

Replace all occurrences of $c$ in $11 = 12 - \frac{c}{3}$ with $3$ .

$11 = 12 - \frac{3}{3}$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.4

Simplify the right side.

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Step 2.3.6.4.1

Simplify $12 - \frac{3}{3}$ .

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Step 2.3.6.4.1.1

Simplify each term.

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Step 2.3.6.4.1.1.1

Cancel the common factor of $3$ .

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Step 2.3.6.4.1.1.1.1

Cancel the common factor.

$11 = 12 - \frac{3}{3}$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.4.1.1.1.2

Rewrite the expression.

$11 = 12 - 1 \cdot 1$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 12 - 1 \cdot 1$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.4.1.1.2

Multiply $- 1$ by $1$ .

$11 = 12 - 1$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 12 - 1$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.4.1.2

Subtract $1$ from $12$ .

$11 = 11$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 11$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

$11 = 11$

$a = 2$

$c = 3$

$131 = 96 + \frac{35 c}{3}$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.5

Replace all occurrences of $c$ in $131 = 96 + \frac{35 c}{3}$ with $3$ .

$131 = 96 + \frac{35 (3)}{3}$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.6

Simplify the right side.

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Step 2.3.6.6.1

Simplify $96 + \frac{35 (3)}{3}$ .

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Step 2.3.6.6.1.1

Multiply $35$ by $3$ .

$131 = 96 + \frac{105}{3}$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.6.1.2

Divide $105$ by $3$ .

$131 = 96 + 35$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.6.1.3

Add $96$ and $35$ .

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - \frac{4 c}{3}$

Step 2.3.6.7

Replace all occurrences of $c$ in $b = 4 - \frac{4 c}{3}$ with $3$ .

$b = 4 - \frac{4 (3)}{3}$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

Step 2.3.6.8

Simplify the right side.

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Step 2.3.6.8.1

Simplify $4 - \frac{4 (3)}{3}$ .

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Step 2.3.6.8.1.1

Simplify each term.

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Step 2.3.6.8.1.1.1

Cancel the common factor of $3$ .

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Step 2.3.6.8.1.1.1.1

Cancel the common factor.

$b = 4 - \frac{4 \cdot 3}{3}$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

Step 2.3.6.8.1.1.1.2

Divide $4$ by $1$ .

$b = 4 - 1 \cdot 4$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - 1 \cdot 4$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

Step 2.3.6.8.1.1.2

Multiply $- 1$ by $4$ .

$b = 4 - 4$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 4 - 4$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

Step 2.3.6.8.1.2

Subtract $4$ from $4$ .

$b = 0$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 0$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 0$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

$b = 0$

$131 = 131$

$11 = 11$

$a = 2$

$c = 3$

Step 2.3.7

Remove any equations from the system that are always true.

$b = 0$

$a = 2$

$c = 3$

Step 2.3.8

List all of the solutions.

$b = 0, a = 2, c = 3$

Step 2.4

Calculate the value of $y$ using each $x$ value in the table and compare this value to the given $q (x)$ value in the table.

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Step 2.4.1

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 2$ , $b = 0$ , $c = 3$ , and $x = 1$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

One to any power is one.

$y = 2 \cdot 1 + (0) \cdot (1) + 3$

Step 2.4.1.1.2

Multiply $2$ by $1$ .

$y = 2 + (0) \cdot (1) + 3$

Step 2.4.1.1.3

Multiply $0$ by $1$ .

$y = 2 + 0 + 3$

Step 2.4.1.2

Simplify by adding numbers.

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Step 2.4.1.2.1

Add $2$ and $0$ .

$y = 2 + 3$

Step 2.4.1.2.2

Add $2$ and $3$ .

$y = 5$

Step 2.4.2

If the table has a quadratic function rule, $y = q (x)$ for the corresponding $x$ value, $x = 1$ . This check passes since $y = 5$ and $q (x) = 5$ .

$5 = 5$

Step 2.4.3

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 2$ , $b = 0$ , $c = 3$ , and $x = 9$ .

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Step 2.4.3.1

Simplify each term.

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Step 2.4.3.1.1

Raise $9$ to the power of $2$ .

$y = 2 \cdot 81 + (0) \cdot (9) + 3$

Step 2.4.3.1.2

Multiply $2$ by $81$ .

$y = 162 + (0) \cdot (9) + 3$

Step 2.4.3.1.3

Multiply $0$ by $9$ .

$y = 162 + 0 + 3$

Step 2.4.3.2

Simplify by adding numbers.

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Step 2.4.3.2.1

Add $162$ and $0$ .

$y = 162 + 3$

Step 2.4.3.2.2

Add $162$ and $3$ .

$y = 165$

Step 2.4.4

If the table has a quadratic function rule, $y = q (x)$ for the corresponding $x$ value, $x = 9$ . This check passes since $y = 165$ and $q (x) = 165$ .

$165 = 165$

Step 2.4.5

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 2$ , $b = 0$ , $c = 3$ , and $x = 2$ .

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Step 2.4.5.1

Simplify each term.

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Step 2.4.5.1.1

Multiply $2$ by ${(2)}^{2}$ by adding the exponents.

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Step 2.4.5.1.1.1

Multiply $2$ by ${(2)}^{2}$ .

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Step 2.4.5.1.1.1.1

Raise $2$ to the power of $1$ .

$y = 2 \cdot {(2)}^{2} + (0) \cdot (2) + 3$

Step 2.4.5.1.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$y = 2^{1 + 2} + (0) \cdot (2) + 3$

Step 2.4.5.1.1.2

Add $1$ and $2$ .

$y = 2^{3} + (0) \cdot (2) + 3$

Step 2.4.5.1.2

Raise $2$ to the power of $3$ .

$y = 8 + (0) \cdot (2) + 3$

Step 2.4.5.1.3

Multiply $0$ by $2$ .

$y = 8 + 0 + 3$

Step 2.4.5.2

Simplify by adding numbers.

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Step 2.4.5.2.1

Add $8$ and $0$ .

$y = 8 + 3$

Step 2.4.5.2.2

Add $8$ and $3$ .

$y = 11$

Step 2.4.6

If the table has a quadratic function rule, $y = q (x)$ for the corresponding $x$ value, $x = 2$ . This check passes since $y = 11$ and $q (x) = 11$ .

$11 = 11$

Step 2.4.7

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 2$ , $b = 0$ , $c = 3$ , and $x = 8$ .

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Step 2.4.7.1

Simplify each term.

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Step 2.4.7.1.1

Raise $8$ to the power of $2$ .

$y = 2 \cdot 64 + (0) \cdot (8) + 3$

Step 2.4.7.1.2

Multiply $2$ by $64$ .

$y = 128 + (0) \cdot (8) + 3$

Step 2.4.7.1.3

Multiply $0$ by $8$ .

$y = 128 + 0 + 3$

Step 2.4.7.2

Simplify by adding numbers.

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Step 2.4.7.2.1

Add $128$ and $0$ .

$y = 128 + 3$

Step 2.4.7.2.2

Add $128$ and $3$ .

$y = 131$

Step 2.4.8

If the table has a quadratic function rule, $y = q (x)$ for the corresponding $x$ value, $x = 8$ . This check passes since $y = 131$ and $q (x) = 131$ .

$131 = 131$

Step 2.4.9

Calculate the value of $y$ such that $y = a x^{2} + b$ when $a = 2$ , $b = 0$ , $c = 3$ , and $x = 3$ .

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Step 2.4.9.1

Simplify each term.

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Step 2.4.9.1.1

Raise $3$ to the power of $2$ .

$y = 2 \cdot 9 + (0) \cdot (3) + 3$

Step 2.4.9.1.2

Multiply $2$ by $9$ .

$y = 18 + (0) \cdot (3) + 3$

Step 2.4.9.1.3

Multiply $0$ by $3$ .

$y = 18 + 0 + 3$

Step 2.4.9.2

Simplify by adding numbers.

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Step 2.4.9.2.1

Add $18$ and $0$ .

$y = 18 + 3$

Step 2.4.9.2.2

Add $18$ and $3$ .

$y = 21$

Step 2.4.10

If the table has a quadratic function rule, $y = q (x)$ for the corresponding $x$ value, $x = 3$ . This check passes since $y = 21$ and $q (x) = 21$ .

$21 = 21$

Step 2.4.11

Since $y = q (x)$ for the corresponding $x$ values, the function is quadratic.

The function is quadratic

Step 3

Since all $y = q (x)$ , the function is quadratic and follows the form $y = 2 x^{2} + 3$ .

$y = 2 x^{2} + 3$

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