Algebra Examples

x^{2} + y = 0

$x^{2} + y = 0$ ,

y = 5 x^{2}

$y = 5 x^{2}$ ,

(0, 0)

$(0, 0)$

Step 1

Simplify

{(0)}^{2} + 0

${(0)}^{2} + 0$ .

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Step 1.1

Raising

0

$0$ to any positive power yields

0

$0$ .

0 + 0 = 0

$0 + 0 = 0$

0 = 5 {(0)}^{2}

$0 = 5 {(0)}^{2}$

Step 1.2

Add

0

$0$ and

0

$0$ .

0 = 0

$0 = 0$

0 = 5 {(0)}^{2}

$0 = 5 {(0)}^{2}$

0 = 0

$0 = 0$

0 = 5 {(0)}^{2}

$0 = 5 {(0)}^{2}$

Step 2

Since

0 = 0

$0 = 0$ , the equation will always be true.

Always true

0 = 5 {(0)}^{2}

$0 = 5 {(0)}^{2}$

Step 3

Simplify

5 \cdot 0^{2}

$5 \cdot 0^{2}$ .

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Step 3.1

Raising

0

$0$ to any positive power yields

0

$0$ .

0 = 5 \cdot 0

$0 = 5 \cdot 0$

Always true

Step 3.2

Multiply

5

$5$ by

0

$0$ .

0 = 0

$0 = 0$

Always true

0 = 0

$0 = 0$

Always true

Step 4

Since

0 = 0

$0 = 0$ , the equation will always be true.

Always true

Step 5

The ordered pair is a solution to the system of equations.

(0, 0)

$(0, 0)$ is a solution

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