Algebra Examples

Solve by Addition/Elimination
4x+y2z=0 , 2x3y+3z=9 , 6x2y+z=0
Step 1
Choose two equations and eliminate one variable. In this case, eliminate y.
4x+y2z=0
2x3y+3z=9
Step 2
Eliminate y from the system.
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Step 2.1
Multiply each equation by the value that makes the coefficients of y opposite.
(3)(4x+y2z)=(3)(0)
2x3y+3z=9
Step 2.2
Simplify.
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Step 2.2.1
Simplify the left side.
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Step 2.2.1.1
Simplify (3)(4x+y2z).
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Step 2.2.1.1.1
Apply the distributive property.
3(4x)+3y+3(2z)=(3)(0)
2x3y+3z=9
Step 2.2.1.1.2
Simplify.
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Step 2.2.1.1.2.1
Multiply 4 by 3.
12x+3y+3(2z)=(3)(0)
2x3y+3z=9
Step 2.2.1.1.2.2
Multiply 2 by 3.
12x+3y6z=(3)(0)
2x3y+3z=9
12x+3y6z=(3)(0)
2x3y+3z=9
12x+3y6z=(3)(0)
2x3y+3z=9
12x+3y6z=(3)(0)
2x3y+3z=9
Step 2.2.2
Simplify the right side.
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Step 2.2.2.1
Multiply 3 by 0.
12x+3y6z=0
2x3y+3z=9
12x+3y6z=0
2x3y+3z=9
12x+3y6z=0
2x3y+3z=9
Step 2.3
Add the two equations together to eliminate y from the system.
12x+3y6z=0
+2x3y+3z=9
14x3z=9
Step 2.4
The resultant equation has y eliminated.
14x3z=9
14x3z=9
Step 3
Choose another two equations and eliminate y.
2x3y+3z=9
6x2y+z=0
Step 4
Eliminate y from the system.
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Step 4.1
Multiply each equation by the value that makes the coefficients of y opposite.
(2)(2x3y+3z)=(2)(9)
(3)(6x2y+z)=(3)(0)
Step 4.2
Simplify.
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Step 4.2.1
Simplify the left side.
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Step 4.2.1.1
Simplify (2)(2x3y+3z).
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Step 4.2.1.1.1
Apply the distributive property.
2(2x)2(3y)2(3z)=(2)(9)
(3)(6x2y+z)=(3)(0)
Step 4.2.1.1.2
Simplify.
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Step 4.2.1.1.2.1
Multiply 2 by 2.
4x2(3y)2(3z)=(2)(9)
(3)(6x2y+z)=(3)(0)
Step 4.2.1.1.2.2
Multiply 3 by 2.
4x+6y2(3z)=(2)(9)
(3)(6x2y+z)=(3)(0)
Step 4.2.1.1.2.3
Multiply 3 by 2.
4x+6y6z=(2)(9)
(3)(6x2y+z)=(3)(0)
4x+6y6z=(2)(9)
(3)(6x2y+z)=(3)(0)
4x+6y6z=(2)(9)
(3)(6x2y+z)=(3)(0)
4x+6y6z=(2)(9)
(3)(6x2y+z)=(3)(0)
Step 4.2.2
Simplify the right side.
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Step 4.2.2.1
Multiply 2 by 9.
4x+6y6z=18
(3)(6x2y+z)=(3)(0)
4x+6y6z=18
(3)(6x2y+z)=(3)(0)
Step 4.2.3
Simplify the left side.
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Step 4.2.3.1
Simplify (3)(6x2y+z).
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Step 4.2.3.1.1
Apply the distributive property.
4x+6y6z=18
3(6x)+3(2y)+3z=(3)(0)
Step 4.2.3.1.2
Simplify.
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Step 4.2.3.1.2.1
Multiply 6 by 3.
4x+6y6z=18
18x+3(2y)+3z=(3)(0)
Step 4.2.3.1.2.2
Multiply 2 by 3.
4x+6y6z=18
18x6y+3z=(3)(0)
4x+6y6z=18
18x6y+3z=(3)(0)
4x+6y6z=18
18x6y+3z=(3)(0)
4x+6y6z=18
18x6y+3z=(3)(0)
Step 4.2.4
Simplify the right side.
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Step 4.2.4.1
Multiply 3 by 0.
4x+6y6z=18
18x6y+3z=0
4x+6y6z=18
18x6y+3z=0
4x+6y6z=18
18x6y+3z=0
Step 4.3
Add the two equations together to eliminate y from the system.
4x+6y6z=18
+18x6y+3z=0
22x3z=18
Step 4.4
The resultant equation has y eliminated.
22x3z=18
22x3z=18
Step 5
Take the resultant equations and eliminate another variable. In this case, eliminate z.
14x3z=9
22x3z=18
Step 6
Eliminate z from the system.
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Step 6.1
Multiply each equation by the value that makes the coefficients of z opposite.
(1)(14x3z)=(1)(9)
22x3z=18
Step 6.2
Simplify.
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Step 6.2.1
Simplify the left side.
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Step 6.2.1.1
Simplify (1)(14x3z).
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Step 6.2.1.1.1
Apply the distributive property.
1(14x)1(3z)=(1)(9)
22x3z=18
Step 6.2.1.1.2
Multiply.
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Step 6.2.1.1.2.1
Multiply 14 by 1.
14x1(3z)=(1)(9)
22x3z=18
Step 6.2.1.1.2.2
Multiply 3 by 1.
14x+3z=(1)(9)
22x3z=18
14x+3z=(1)(9)
22x3z=18
14x+3z=(1)(9)
22x3z=18
14x+3z=(1)(9)
22x3z=18
Step 6.2.2
Simplify the right side.
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Step 6.2.2.1
Multiply 1 by 9.
14x+3z=9
22x3z=18
14x+3z=9
22x3z=18
14x+3z=9
22x3z=18
Step 6.3
Add the two equations together to eliminate z from the system.
14x+3z=9
+22x3z=18
36x=27
Step 6.4
The resultant equation has z eliminated.
36x=27
Step 6.5
Divide each term in 36x=27 by 36 and simplify.
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Step 6.5.1
Divide each term in 36x=27 by 36.
36x36=2736
Step 6.5.2
Simplify the left side.
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Step 6.5.2.1
Cancel the common factor of 36.
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Step 6.5.2.1.1
Cancel the common factor.
36x36=2736
Step 6.5.2.1.2
Divide x by 1.
x=2736
x=2736
x=2736
Step 6.5.3
Simplify the right side.
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Step 6.5.3.1
Cancel the common factor of 27 and 36.
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Step 6.5.3.1.1
Factor 9 out of 27.
x=9(3)36
Step 6.5.3.1.2
Cancel the common factors.
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Step 6.5.3.1.2.1
Factor 9 out of 36.
x=9394
Step 6.5.3.1.2.2
Cancel the common factor.
x=9394
Step 6.5.3.1.2.3
Rewrite the expression.
x=34
x=34
x=34
x=34
x=34
x=34
Step 7
Substitute the value of x into an equation with y eliminated already and solve for the remaining variable.
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Step 7.1
Substitute the value of x into an equation with y eliminated already.
14(34)3z=9
Step 7.2
Solve for z.
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Step 7.2.1
Simplify each term.
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Step 7.2.1.1
Cancel the common factor of 2.
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Step 7.2.1.1.1
Factor 2 out of 14.
2(7)343z=9
Step 7.2.1.1.2
Factor 2 out of 4.
273223z=9
Step 7.2.1.1.3
Cancel the common factor.
273223z=9
Step 7.2.1.1.4
Rewrite the expression.
7(32)3z=9
7(32)3z=9
Step 7.2.1.2
Combine 7 and 32.
7323z=9
Step 7.2.1.3
Multiply 7 by 3.
2123z=9
2123z=9
Step 7.2.2
Move all terms not containing z to the right side of the equation.
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Step 7.2.2.1
Subtract 212 from both sides of the equation.
3z=9212
Step 7.2.2.2
To write 9 as a fraction with a common denominator, multiply by 22.
3z=922212
Step 7.2.2.3
Combine 9 and 22.
3z=922212
Step 7.2.2.4
Combine the numerators over the common denominator.
3z=92212
Step 7.2.2.5
Simplify the numerator.
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Step 7.2.2.5.1
Multiply 9 by 2.
3z=18212
Step 7.2.2.5.2
Subtract 21 from 18.
3z=32
3z=32
Step 7.2.2.6
Move the negative in front of the fraction.
3z=32
3z=32
Step 7.2.3
Divide each term in 3z=32 by 3 and simplify.
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Step 7.2.3.1
Divide each term in 3z=32 by 3.
3z3=323
Step 7.2.3.2
Simplify the left side.
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Step 7.2.3.2.1
Cancel the common factor of 3.
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Step 7.2.3.2.1.1
Cancel the common factor.
3z3=323
Step 7.2.3.2.1.2
Divide z by 1.
z=323
z=323
z=323
Step 7.2.3.3
Simplify the right side.
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Step 7.2.3.3.1
Multiply the numerator by the reciprocal of the denominator.
z=3213
Step 7.2.3.3.2
Cancel the common factor of 3.
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Step 7.2.3.3.2.1
Move the leading negative in 32 into the numerator.
z=3213
Step 7.2.3.3.2.2
Factor 3 out of 3.
z=3(1)213
Step 7.2.3.3.2.3
Factor 3 out of 3.
z=312131
Step 7.2.3.3.2.4
Cancel the common factor.
z=312131
Step 7.2.3.3.2.5
Rewrite the expression.
z=1211
z=1211
Step 7.2.3.3.3
Multiply 12 by 11.
z=121
Step 7.2.3.3.4
Multiply 2 by 1.
z=12
Step 7.2.3.3.5
Dividing two negative values results in a positive value.
z=12
z=12
z=12
z=12
z=12
Step 8
Substitute the value of each known variable into one of the initial equations and solve for the last variable.
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Step 8.1
Substitute the value of each known variable into one of the initial equations.
4(34)+y2(12)=0
Step 8.2
Solve for y.
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Step 8.2.1
Simplify 4(34)+y2(12).
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Step 8.2.1.1
Simplify each term.
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Step 8.2.1.1.1
Cancel the common factor of 4.
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Step 8.2.1.1.1.1
Cancel the common factor.
4(34)+y2(12)=0
Step 8.2.1.1.1.2
Rewrite the expression.
3+y2(12)=0
3+y2(12)=0
Step 8.2.1.1.2
Cancel the common factor of 2.
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Step 8.2.1.1.2.1
Factor 2 out of 2.
3+y+2(1)12=0
Step 8.2.1.1.2.2
Cancel the common factor.
3+y+2112=0
Step 8.2.1.1.2.3
Rewrite the expression.
3+y1=0
3+y1=0
3+y1=0
Step 8.2.1.2
Subtract 1 from 3.
y+2=0
y+2=0
Step 8.2.2
Subtract 2 from both sides of the equation.
y=2
y=2
y=2
Step 9
The solution to the system of equations can be represented as a point.
(34,2,12)
Step 10
The result can be shown in multiple forms.
Point Form:
(34,2,12)
Equation Form:
x=34,y=2,z=12
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