Algebra Examples
(2x3-x2-48x+15)÷(x-5)(2x3−x2−48x+15)÷(x−5)
Step 1
Place the numbers representing the divisor and the dividend into a division-like configuration.
55 | 22 | -1−1 | -48−48 | 1515 |
Step 2
The first number in the dividend (2)(2) is put into the first position of the result area (below the horizontal line).
55 | 22 | -1−1 | -48−48 | 1515 |
22 |
Step 3
Multiply the newest entry in the result (2)(2) by the divisor (5)(5) and place the result of (10)(10) under the next term in the dividend (-1)(−1).
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | ||||
22 |
Step 4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | ||||
22 | 99 |
Step 5
Multiply the newest entry in the result (9)(9) by the divisor (5)(5) and place the result of (45)(45) under the next term in the dividend (-48)(−48).
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | 4545 | |||
22 | 99 |
Step 6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | 4545 | |||
22 | 99 | -3−3 |
Step 7
Multiply the newest entry in the result (-3)(−3) by the divisor (5)(5) and place the result of (-15)(−15) under the next term in the dividend (15)(15).
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | 4545 | -15−15 | ||
22 | 99 | -3−3 |
Step 8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
55 | 22 | -1−1 | -48−48 | 1515 |
1010 | 4545 | -15−15 | ||
22 | 99 | -3−3 | 00 |
Step 9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
2x2+9x-32x2+9x−3