Algebra Examples

Solve Using the Quadratic Formula
x2+2x-15=0
Step 1
Use the quadratic formula to find the solutions.
-b±b2-4(ac)2a
Step 2
Substitute the values a=1, b=2, and c=-15 into the quadratic formula and solve for x.
-2±22-4(1-15)21
Step 3
Simplify.
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Step 3.1
Simplify the numerator.
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Step 3.1.1
Raise 2 to the power of 2.
x=-2±4-41-1521
Step 3.1.2
Multiply -41-15.
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Step 3.1.2.1
Multiply -4 by 1.
x=-2±4-4-1521
Step 3.1.2.2
Multiply -4 by -15.
x=-2±4+6021
x=-2±4+6021
Step 3.1.3
Add 4 and 60.
x=-2±6421
Step 3.1.4
Rewrite 64 as 82.
x=-2±8221
Step 3.1.5
Pull terms out from under the radical, assuming positive real numbers.
x=-2±821
x=-2±821
Step 3.2
Multiply 2 by 1.
x=-2±82
Step 3.3
Simplify -2±82.
x=-1±4
x=-1±4
Step 4
The final answer is the combination of both solutions.
x=3,-5
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 [x2  12  π  xdx ] 
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