Algebra Examples

x^{2} - 5 x - 6 = 9

$x^{2} - 5 x - 6 = 9$

Step 1

Move all terms to the left side of the equation and simplify.

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Step 1.1

Subtract

9

$9$ from both sides of the equation.

x^{2} - 5 x - 6 - 9 = 0

$x^{2} - 5 x - 6 - 9 = 0$

Step 1.2

Subtract

9

$9$ from

- 6

$- 6$ .

x^{2} - 5 x - 15 = 0

$x^{2} - 5 x - 15 = 0$

x^{2} - 5 x - 15 = 0

$x^{2} - 5 x - 15 = 0$

Step 2

Once the quadratic is in standard form, the values of

a

$a$ ,

b

$b$ , and

c

$c$ can be found.

a x^{2} + b x + c

$a x^{2} + b x + c$

Step 3

Use the standard form of the equation to find

a

$a$ ,

b

$b$ , and

c

$c$ for this quadratic.

a = 1

$a = 1$ ,

b = - 5

$b = - 5$ ,

c = - 15

$c = - 15$

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