Algebra Examples

(- 7, - 1)

$(- 7, - 1)$ ,

m = 2

$m = 2$

Step 1

Use the slope

2

$2$ and a given point

(- 7, - 1)

$(- 7, - 1)$ to substitute for

x_{1}

$x_{1}$ and

y_{1}

$y_{1}$ in the point-slope form

y - y_{1} = m (x - x_{1})

$y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation

m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}

$m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

y - (- 1) = 2 \cdot (x - (- 7))

$y - (- 1) = 2 \cdot (x - (- 7))$

Step 2

Simplify the equation and keep it in point-slope form.

y + 1 = 2 \cdot (x + 7)

$y + 1 = 2 \cdot (x + 7)$

Step 3

Solve for

y

$y$ .

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Step 3.1

Simplify

2 \cdot (x + 7)

$2 \cdot (x + 7)$ .

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Step 3.1.1

Rewrite.

y + 1 = 0 + 0 + 2 \cdot (x + 7)

$y + 1 = 0 + 0 + 2 \cdot (x + 7)$

Step 3.1.2

Simplify by adding zeros.

y + 1 = 2 \cdot (x + 7)

$y + 1 = 2 \cdot (x + 7)$

Step 3.1.3

Apply the distributive property.

y + 1 = 2 x + 2 \cdot 7

$y + 1 = 2 x + 2 \cdot 7$

Step 3.1.4

Multiply

2

$2$ by

7

$7$ .

y + 1 = 2 x + 14

$y + 1 = 2 x + 14$

y + 1 = 2 x + 14

$y + 1 = 2 x + 14$

Step 3.2

Move all terms not containing

y

$y$ to the right side of the equation.

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Step 3.2.1

Subtract

1

$1$ from both sides of the equation.

y = 2 x + 14 - 1

$y = 2 x + 14 - 1$

Step 3.2.2

Subtract

1

$1$ from

14

$14$ .

y = 2 x + 13

$y = 2 x + 13$

y = 2 x + 13

$y = 2 x + 13$

y = 2 x + 13

$y = 2 x + 13$

Step 4

List the equation in different forms.

Slope-intercept form:

y = 2 x + 13

$y = 2 x + 13$

Point-slope form:

y + 1 = 2 \cdot (x + 7)

$y + 1 = 2 \cdot (x + 7)$

Step 5

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