Algebra Examples
x4-2x3-10x2+7x+4 , x-1
Step 1
Step 1.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
1 | 1 | -2 | -10 | 7 | 4 |
Step 1.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
1 | 1 | -2 | -10 | 7 | 4 |
1 |
Step 1.3
Multiply the newest entry in the result (1) by the divisor (1) and place the result of (1) under the next term in the dividend (-2).
1 | 1 | -2 | -10 | 7 | 4 |
1 | |||||
1 |
Step 1.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | -2 | -10 | 7 | 4 |
1 | |||||
1 | -1 |
Step 1.5
Multiply the newest entry in the result (-1) by the divisor (1) and place the result of (-1) under the next term in the dividend (-10).
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | ||||
1 | -1 |
Step 1.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | ||||
1 | -1 | -11 |
Step 1.7
Multiply the newest entry in the result (-11) by the divisor (1) and place the result of (-11) under the next term in the dividend (7).
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | -11 | |||
1 | -1 | -11 |
Step 1.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | -11 | |||
1 | -1 | -11 | -4 |
Step 1.9
Multiply the newest entry in the result (-4) by the divisor (1) and place the result of (-4) under the next term in the dividend (4).
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | -11 | -4 | ||
1 | -1 | -11 | -4 |
Step 1.10
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | -2 | -10 | 7 | 4 |
1 | -1 | -11 | -4 | ||
1 | -1 | -11 | -4 | 0 |
Step 1.11
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x3+-1x2+(-11)x-4
Step 1.12
Simplify the quotient polynomial.
x3-x2-11x-4
x3-x2-11x-4
Step 2
The remainder from dividing x4-2x3-10x2+7x+4x-1 is 0, which means that x-1 is a factor for x4-2x3-10x2+7x+4.
x-1 is a factor for x4-2x3-10x2+7x+4
Step 3
Step 3.1
If a polynomial function has integer coefficients, then every rational zero will have the form pq where p is a factor of the constant and q is a factor of the leading coefficient.
p=±1,±2,±4
q=±1
Step 3.2
Find every combination of ±pq. These are the possible roots of the polynomial function.
±1,±2,±4
±1,±2,±4
Step 4
Set up the next division to determine if x-4 is a factor of the polynomial x3-x2-11x-4.
x3-x2-11x-4x-4
Step 5
Step 5.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
4 | 1 | -1 | -11 | -4 |
Step 5.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
4 | 1 | -1 | -11 | -4 |
1 |
Step 5.3
Multiply the newest entry in the result (1) by the divisor (4) and place the result of (4) under the next term in the dividend (-1).
4 | 1 | -1 | -11 | -4 |
4 | ||||
1 |
Step 5.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | -1 | -11 | -4 |
4 | ||||
1 | 3 |
Step 5.5
Multiply the newest entry in the result (3) by the divisor (4) and place the result of (12) under the next term in the dividend (-11).
4 | 1 | -1 | -11 | -4 |
4 | 12 | |||
1 | 3 |
Step 5.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | -1 | -11 | -4 |
4 | 12 | |||
1 | 3 | 1 |
Step 5.7
Multiply the newest entry in the result (1) by the divisor (4) and place the result of (4) under the next term in the dividend (-4).
4 | 1 | -1 | -11 | -4 |
4 | 12 | 4 | ||
1 | 3 | 1 |
Step 5.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
4 | 1 | -1 | -11 | -4 |
4 | 12 | 4 | ||
1 | 3 | 1 | 0 |
Step 5.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x2+3x+1
Step 5.10
Simplify the quotient polynomial.
x2+3x+1
x2+3x+1
Step 6
Step 6.1
If a polynomial function has integer coefficients, then every rational zero will have the form pq where p is a factor of the constant and q is a factor of the leading coefficient.
p=±1
q=±1
Step 6.2
Find every combination of ±pq. These are the possible roots of the polynomial function.
±1
±1
Step 7
The final factor is the only factor left over from the synthetic division.
x2+3x+1
Step 8
The factored polynomial is (x-1)(x-4)(x2+3x+1).
(x-1)(x-4)(x2+3x+1)