Algebra Examples

x3-27x327
Step 1
Rewrite 2727 as 3333.
x3-33x333
Step 2
Since both terms are perfect cubes, factor using the difference of cubes formula, a3-b3=(a-b)(a2+ab+b2)a3b3=(ab)(a2+ab+b2) where a=xa=x and b=3b=3.
(x-3)(x2+x3+32)(x3)(x2+x3+32)
Step 3
Simplify.
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Step 3.1
Move 33 to the left of xx.
(x-3)(x2+3x+32)(x3)(x2+3x+32)
Step 3.2
Raise 33 to the power of 22.
(x-3)(x2+3x+9)(x3)(x2+3x+9)
(x-3)(x2+3x+9)(x3)(x2+3x+9)
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 [x2  12  π  xdx ]  x2  12  π  xdx  
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