Algebra Examples

{(x - 9)}^{3}

${(x - 9)}^{3}$

Step 1

Use the binomial expansion theorem to find each term. The binomial theorem states

{(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})

${(a + b)}^{n} = \sum_{k = 0}^{n} n C k \cdot (a^{n - k} b^{k})$ .

\sum_{k = 0}^{3} \frac{3!}{(3 - k)! k!} \cdot {(x)}^{3 - k} \cdot {(- 9)}^{k}

$\sum_{k = 0}^{3} \frac{3!}{(3 - k)! k!} \cdot {(x)}^{3 - k} \cdot {(- 9)}^{k}$

Step 2

Expand the summation.

\frac{3!}{(3 - 0)! 0!} {(x)}^{3 - 0} \cdot {(- 9)}^{0} + \frac{3!}{(3 - 1)! 1!} {(x)}^{3 - 1} \cdot {(- 9)}^{1} + \frac{3!}{(3 - 2)! 2!} {(x)}^{3 - 2} \cdot {(- 9)}^{2} + \frac{3!}{(3 - 3)! 3!} {(x)}^{3 - 3} \cdot {(- 9)}^{3}

$\frac{3!}{(3 - 0)! 0!} {(x)}^{3 - 0} \cdot {(- 9)}^{0} + \frac{3!}{(3 - 1)! 1!} {(x)}^{3 - 1} \cdot {(- 9)}^{1} + \frac{3!}{(3 - 2)! 2!} {(x)}^{3 - 2} \cdot {(- 9)}^{2} + \frac{3!}{(3 - 3)! 3!} {(x)}^{3 - 3} \cdot {(- 9)}^{3}$

Step 3

Simplify the exponents for each term of the expansion.

1 \cdot {(x)}^{3} \cdot {(- 9)}^{0} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$1 \cdot {(x)}^{3} \cdot {(- 9)}^{0} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4

Simplify each term.

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Step 4.1

Multiply

{(x)}^{3}

${(x)}^{3}$ by

1

$1$ .

{(x)}^{3} \cdot {(- 9)}^{0} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

${(x)}^{3} \cdot {(- 9)}^{0} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.2

Anything raised to

0

$0$ is

1

$1$ .

x^{3} \cdot 1 + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} \cdot 1 + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.3

Multiply

x^{3}

$x^{3}$ by

1

$1$ .

x^{3} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} + 3 \cdot {(x)}^{2} \cdot {(- 9)}^{1} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.4

Evaluate the exponent.

x^{3} + 3 x^{2} \cdot - 9 + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} + 3 x^{2} \cdot - 9 + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.5

Multiply

- 9

$- 9$ by

3

$3$ .

x^{3} - 27 x^{2} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 3 \cdot {(x)}^{1} \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.6

Simplify.

x^{3} - 27 x^{2} + 3 \cdot x \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 3 \cdot x \cdot {(- 9)}^{2} + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.7

Raise

- 9

$- 9$ to the power of

2

$2$ .

x^{3} - 27 x^{2} + 3 x \cdot 81 + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 3 x \cdot 81 + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.8

Multiply

81

$81$ by

3

$3$ .

x^{3} - 27 x^{2} + 243 x + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 243 x + 1 \cdot {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.9

Multiply

{(x)}^{0}

${(x)}^{0}$ by

1

$1$ .

x^{3} - 27 x^{2} + 243 x + {(x)}^{0} \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 243 x + {(x)}^{0} \cdot {(- 9)}^{3}$

Step 4.10

Anything raised to

0

$0$ is

1

$1$ .

x^{3} - 27 x^{2} + 243 x + 1 \cdot {(- 9)}^{3}

$x^{3} - 27 x^{2} + 243 x + 1 \cdot {(- 9)}^{3}$

Step 4.11

Multiply

{(- 9)}^{3}

${(- 9)}^{3}$ by

1

$1$ .

x^{3} - 27 x^{2} + 243 x + {(- 9)}^{3}

$x^{3} - 27 x^{2} + 243 x + {(- 9)}^{3}$

Step 4.12

Raise

- 9

$- 9$ to the power of

3

$3$ .

x^{3} - 27 x^{2} + 243 x - 729

$x^{3} - 27 x^{2} + 243 x - 729$

x^{3} - 27 x^{2} + 243 x - 729

$x^{3} - 27 x^{2} + 243 x - 729$

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