Algebra Examples

$6 x - 2 y + x^{2} + y^{2} = 1$

Step 1

Complete the square for $6 x + x^{2}$ .

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Step 1.1

Reorder $6 x$ and $x^{2}$ .

$x^{2} + 6 x$

Step 1.2

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = 6$

$c = 0$

Step 1.3

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 1.4

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 1.4.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{6}{2 \cdot 1}$

Step 1.4.2

Cancel the common factor of $6$ and $2$ .

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Step 1.4.2.1

Factor $2$ out of $6$ .

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Step 1.4.2.2

Cancel the common factors.

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Step 1.4.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot 3}{2 (1)}$

Step 1.4.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot 3}{2 \cdot 1}$

Step 1.4.2.2.3

Rewrite the expression.

$d = \frac{3}{1}$

Step 1.4.2.2.4

Divide $3$ by $1$ .

$d = 3$

Step 1.5

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 1.5.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{6^{2}}{4 \cdot 1}$

Step 1.5.2

Simplify the right side.

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Step 1.5.2.1

Simplify each term.

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Step 1.5.2.1.1

Raise $6$ to the power of $2$ .

$e = 0 - \frac{36}{4 \cdot 1}$

Step 1.5.2.1.2

Multiply $4$ by $1$ .

$e = 0 - \frac{36}{4}$

Step 1.5.2.1.3

Divide $36$ by $4$ .

$e = 0 - 1 \cdot 9$

Step 1.5.2.1.4

Multiply $- 1$ by $9$ .

$e = 0 - 9$

Step 1.5.2.2

Subtract $9$ from $0$ .

$e = - 9$

Step 1.6

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(x + 3)}^{2} - 9$ .

${(x + 3)}^{2} - 9$

Step 2

Substitute ${(x + 3)}^{2} - 9$ for $6 x + x^{2}$ in the equation $6 x - 2 y + x^{2} + y^{2} = 1$ .

${(x + 3)}^{2} - 9 - 2 y + y^{2} = 1$

Step 3

Move $- 9$ to the right side of the equation by adding $9$ to both sides.

${(x + 3)}^{2} - 2 y + y^{2} = 1 + 9$

Step 4

Complete the square for $- 2 y + y^{2}$ .

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Step 4.1

Reorder $- 2 y$ and $y^{2}$ .

$y^{2} - 2 y$

Step 4.2

Use the form $a x^{2} + b x + c$ , to find the values of $a$ , $b$ , and $c$ .

$a = 1$

$b = - 2$

$c = 0$

Step 4.3

Consider the vertex form of a parabola.

$a {(x + d)}^{2} + e$

Step 4.4

Find the value of $d$ using the formula $d = \frac{b}{2 a}$ .

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Step 4.4.1

Substitute the values of $a$ and $b$ into the formula $d = \frac{b}{2 a}$ .

$d = \frac{- 2}{2 \cdot 1}$

Step 4.4.2

Cancel the common factor of $- 2$ and $2$ .

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Step 4.4.2.1

Factor $2$ out of $- 2$ .

$d = \frac{2 \cdot - 1}{2 \cdot 1}$

Step 4.4.2.2

Cancel the common factors.

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Step 4.4.2.2.1

Factor $2$ out of $2 \cdot 1$ .

$d = \frac{2 \cdot - 1}{2 (1)}$

Step 4.4.2.2.2

Cancel the common factor.

$d = \frac{2 \cdot - 1}{2 \cdot 1}$

Step 4.4.2.2.3

Rewrite the expression.

$d = \frac{- 1}{1}$

Step 4.4.2.2.4

Divide $- 1$ by $1$ .

$d = - 1$

Step 4.5

Find the value of $e$ using the formula $e = c - \frac{b^{2}}{4 a}$ .

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Step 4.5.1

Substitute the values of $c$ , $b$ and $a$ into the formula $e = c - \frac{b^{2}}{4 a}$ .

$e = 0 - \frac{{(- 2)}^{2}}{4 \cdot 1}$

Step 4.5.2

Simplify the right side.

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Step 4.5.2.1

Simplify each term.

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Step 4.5.2.1.1

Raise $- 2$ to the power of $2$ .

$e = 0 - \frac{4}{4 \cdot 1}$

Step 4.5.2.1.2

Multiply $4$ by $1$ .

$e = 0 - \frac{4}{4}$

Step 4.5.2.1.3

Cancel the common factor of $4$ .

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Step 4.5.2.1.3.1

Cancel the common factor.

$e = 0 - \frac{4}{4}$

Step 4.5.2.1.3.2

Rewrite the expression.

$e = 0 - 1 \cdot 1$

Step 4.5.2.1.4

Multiply $- 1$ by $1$ .

$e = 0 - 1$

Step 4.5.2.2

Subtract $1$ from $0$ .

$e = - 1$

Step 4.6

Substitute the values of $a$ , $d$ , and $e$ into the vertex form ${(y - 1)}^{2} - 1$ .

${(y - 1)}^{2} - 1$

Step 5

Substitute ${(y - 1)}^{2} - 1$ for $- 2 y + y^{2}$ in the equation $6 x - 2 y + x^{2} + y^{2} = 1$ .

${(x + 3)}^{2} + {(y - 1)}^{2} - 1 = 1 + 9$

Step 6

Move $- 1$ to the right side of the equation by adding $1$ to both sides.

${(x + 3)}^{2} + {(y - 1)}^{2} = 1 + 9 + 1$

Step 7

Simplify $1 + 9 + 1$ .

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Step 7.1

Add $1$ and $9$ .

${(x + 3)}^{2} + {(y - 1)}^{2} = 10 + 1$

Step 7.2

Add $10$ and $1$ .

${(x + 3)}^{2} + {(y - 1)}^{2} = 11$

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