Algebra Examples

Find the Standard Form of the Parabola
f(x)=4(x+2)2+5
Step 1
Write f(x)=4(x+2)2+5 as an equation.
y=4(x+2)2+5
Step 2
Since x is on the right side of the equation, switch the sides so it is on the left side of the equation.
4(x+2)2+5=y
Step 3
Subtract 5 from both sides of the equation.
4(x+2)2=y5
Step 4
Divide each term in 4(x+2)2=y5 by 4 and simplify.
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Step 4.1
Divide each term in 4(x+2)2=y5 by 4.
4(x+2)24=y4+54
Step 4.2
Simplify the left side.
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Step 4.2.1
Cancel the common factor of 4.
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Step 4.2.1.1
Cancel the common factor.
4(x+2)24=y4+54
Step 4.2.1.2
Divide (x+2)2 by 1.
(x+2)2=y4+54
(x+2)2=y4+54
(x+2)2=y4+54
Step 4.3
Simplify the right side.
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Step 4.3.1
Simplify each term.
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Step 4.3.1.1
Move the negative in front of the fraction.
(x+2)2=y4+54
Step 4.3.1.2
Dividing two negative values results in a positive value.
(x+2)2=y4+54
(x+2)2=y4+54
(x+2)2=y4+54
(x+2)2=y4+54
Step 5
Factor.
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Step 5.1
Combine the numerators over the common denominator.
(x+2)2=y+54
Step 5.2
Factor 1 out of y.
(x+2)2=(y)+54
Step 5.3
Rewrite 5 as 1(5).
(x+2)2=(y)1(5)4
Step 5.4
Factor 1 out of (y)1(5).
(x+2)2=(y5)4
Step 5.5
Move the negative in front of the fraction.
(x+2)2=y54
Step 5.6
Reorder terms.
(x+2)2=(14(y5))
Step 5.7
Remove parentheses.
(x+2)2=14(y5)
(x+2)2=14(y5)
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