Algebra Examples

2+2=|2x|2+2=|2x|
Step 1
Rewrite the equation as |2x|=2+2|2x|=2+2.
|2x|=2+2|2x|=2+2
Step 2
Add 22 and 22.
|2x|=4|2x|=4
Step 3
Remove the absolute value term. This creates a ±± on the right side of the equation because |x|=±x|x|=±x.
2x=±42x=±4
Step 4
The complete solution is the result of both the positive and negative portions of the solution.
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Step 4.1
First, use the positive value of the ±± to find the first solution.
2x=42x=4
Step 4.2
Divide each term in 2x=42x=4 by 22 and simplify.
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Step 4.2.1
Divide each term in 2x=42x=4 by 22.
2x2=422x2=42
Step 4.2.2
Simplify the left side.
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Step 4.2.2.1
Cancel the common factor of 22.
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Step 4.2.2.1.1
Cancel the common factor.
2x2=42
Step 4.2.2.1.2
Divide x by 1.
x=42
x=42
x=42
Step 4.2.3
Simplify the right side.
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Step 4.2.3.1
Divide 4 by 2.
x=2
x=2
x=2
Step 4.3
Next, use the negative value of the ± to find the second solution.
2x=-4
Step 4.4
Divide each term in 2x=-4 by 2 and simplify.
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Step 4.4.1
Divide each term in 2x=-4 by 2.
2x2=-42
Step 4.4.2
Simplify the left side.
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Step 4.4.2.1
Cancel the common factor of 2.
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Step 4.4.2.1.1
Cancel the common factor.
2x2=-42
Step 4.4.2.1.2
Divide x by 1.
x=-42
x=-42
x=-42
Step 4.4.3
Simplify the right side.
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Step 4.4.3.1
Divide -4 by 2.
x=-2
x=-2
x=-2
Step 4.5
The complete solution is the result of both the positive and negative portions of the solution.
x=2,-2
x=2,-2
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